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# flamebirde

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A hint:
2. ## The answer should be plain to see

Nope. Look more at the first line: what's the "mother's blessing"? I think Molly understood that.
3. ## The answer should be plain to see

Nope. Bit more common than that.
4. ## The answer should be plain to see

As pure in shade as mother's blessing true, And yet in form I'm still possessing, too; Partner both in math and drinking I was born of man's quick thinking

6. ## I’m not a gardener

Something that should be odd, but in this case is even, which makes it a symbol of good luck. hmm...

#3: #1:

9. ## Random triangles in a circle

A thought: More thoughts:
10. ## I'm Back

I'm very much interested. I recognize the name, too! I expect great things, my friend.
11. ## Digging Probabilities

Very nice! Well done!
12. ## Digging Probabilities

Question 1: Questions 2 and 3 are correct! Followup question: What are the chances I get the health from the 14th dig versus the 15th dig? Do they differ significantly?

14. ## Jelly beans join the clean plate club

Especially when you consider as well that at any point you've got an extra plate either to transfer to or to transfer from (although that does complicate things a bit, it also ensures that pairs such as {4,8} are solvable).
15. ## Jelly beans join the clean plate club

But no matter what you'll always have at least one pair whose average is even. Try it: pick any three numbers such that the average of any two is odd. I'm fairly sure it's impossible, since between a+b, b+c, and a+c at least one is guaranteed to be even. Do you have another counterexample of two numbers whose average is even but can't be reached via doubling?
16. ## Jelly beans join the clean plate club

I think I've gotten closer.
17. ## Jelly beans join the clean plate club

Aw man, I was so confident I'd finally solved one of Bonanova's legendary puzzles. A start on thinking:
18. ## Largest unit sphere

Nice, thanks!

20. ## Largest unit sphere

Question: the process shown demonstrates a local maximum for the function, but is there a way to prove that (for instance) at n=1000 it doesn't suddenly reach a new maximum? (I guess what I'm trying to say is, is there a proof, or is the solution presented here just process of elimination?)

24. ## Westworld Mafia

I didn't say anything because then I thought about the save's 50/50 to lose their vote the next day. When I went for the tie originally, I thought it would be a sure fire way to gain an advantage, but after the lynch I was left wondering about other possible vote manips. For the record, you had me fooled -- I figured Plasmid had to be a baddie considering everyone else had claimed, but then he claimed too and I saw the logic in his plan. I think Dolores may have been too powerful in the end. Having 2 different vote manips and a lynch save, on top of a kill and a save -- that rendered the baddie's vote manip practically useless in the endgame when roles were revealed. The "once per game" aspect of the actions never mattered because 1. I didn't use anything N1 and 2. The game was 2 nights long. The only way to neuter the role would be to block, which no sane person would do as discussed earlier (no one would use the block ability N1 for this exact reason: you might hit Dolores). But this may all be because of an inactive Indy: that was the only force opposing the goodies that could effectively counter a known Dolores (RID kill, and the block+save to a lesser extent).
25. ## Westworld Mafia

this was one of the situations I had wanted when I went for the tie. Sure, it let the baddie control the lynch, but if he used his vote manip there then in the endgame he would lose since I had both still hidden up my sleeve (of course, that all depended on whether or not I lived). The other option was that the tie went through and no one died, leading to more time for the goodies to figure out the game. That was a good play by Plasmid at the end; it clearly worked out. Congrats to him and to all the goodies! Also, rip Aura who died twice in two consecutive phases
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