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fb- Joe is trying to sell you his share. You are paying him the $200... if you accept his offer. A question
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Les Koller changed their profile photo
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Mining gold in a particular region is hard work. The metal only appears in 1% of rocks in the mine. But your friend Old Joe created a detector he’s been perfecting for months and it is finally ready. To your astonishment it always detect gold if gold is present. Otherwise it will have a 90% accuracy rate in detecting that a particular rock does not have gold. Working with Old Joe, You guys scan a large rock and determine that it gives a positive result. In loading it up, Old Joe realizes that both of you can't fit into the vehicle. He offers to sell his share to you for $200. You know that a rock of gold that size is worth easily $1000. Is that a fair price? Assume the vehicle remains with the proper owner.
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gouravmishra joined the community
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kapilsinghal122 joined the community
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Half way?
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hihihi changed their profile photo
- Last week
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Tinku VNCK changed their profile photo
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assuming five apples in each bowl,
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There are two bowls that you and a challenger must eat from. After flipping a coin you were selected to pick the bowl that each would eat from. In the first bowl there are three out of five poisonous apples. In the second bowl, there are two out of five poisonous apples. Whoever eats from the first bowl must eat two apples at random from the bowl. Whoever eats from the second bowl must eat three random apples from the second bowl. Which bowl should you pick to eat?
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ugenalways2014 changed their profile photo
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Geez! ... How do these "fossil" questions keep surfacing?
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Deleted!
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xxxcyter23 changed their profile photo
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John Rei Marquez changed their profile photo
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Dragos73 changed their profile photo
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Thank you. He did figure it out after I posted.
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SAMANYU joined the community
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wvrandym2000 changed their profile photo
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Good guess . . . Right track. Go lower : )
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andy.usyd changed their profile photo
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Rj Solamo changed their profile photo
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I'll count being in any way confused for Shakee as high praise. As for this one
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You've probably seen this puzzle. There are 15 holes in triangular array. (See sketch below.) The game begins with pegs in 14 of the holes. The play is to jump pegs over adjacent pegs, removing the "jumped" pegs afterward, as in checkers. The jump is made in a straight line. To make a jump, you need a contiguous group consisting of { peg1, peg2, hole } in a straight line. Peg1 ends up in the hole, and peg2 is removed. The object is to make 13 legal jumps and end up with a single peg. This happens about 6% of the time. That is, about 94% of the time you get a configuration, with more than one peg remaining, that permits no further legal jumps. In some games the peg must end up in the original empty hole, and that happens only about 3% of the time. So, it's not a trivial puzzle. This puzzle asks for something different, and easier: Lose as badly as possible. That is, select a location for the empty hole, and then find a sequence of moves that leaves the greatest number of pegs on the board where there are no more legal jumps. It's simple enough to play, even without the game, by marking hole locations on a sheet of paper and using pennies. As already stated, there are 15 holes. There are also 36 possible jumps. For convenience in writing sequences of jumps, they can be numbered, as follows: Number the jumps like this: and the holes ---------------------------> o ------------- 1 So Jump #1 means the / \ like this: peg in hole #1 jumps 1 2 ----------> 2 3 over the peg in hole #2 into the empty 4 5 6 hole #4. o o / \ / \ 7 8 9 10 Jump #18 is peg 7 3 4 5 6 over peg 8, into 7 13 11 12 13 14 15 hole 9. / \ o-8 o 14-o Holes 4, 6, 13 / \ / \ / \ begin 4 jumps; 9 10 11 12 15 16 the others 17 19 21 23 begin two. / / \ \ o-18 o-20 22-o 24-o There are 36 jumps. 25 27 29 30 33 35 / / \ / \ \ o-26 o-28 31-o-32 34-o 36-o With symmetries taken into account, the holes have four equivalence classes: Corners (1, 11, 15) Adjacent to corners (2, 3, 7, 10, 12, 14) Edge centers (4, 6, 13) Centers (5, 8, 9) This means that there are just four distinct places for the empty hole to start a game: { 1 2 4 5 }. All other holes are symmetrically equivalent to one of these. Just to be sure the numbering above is understood, here is a winning game of the normal type. Start with pegs in every hole except #1. (The top hole is empty.) Then make these jumps: { 7 14 2 17 23 27 34 26 30 6 35 14 7 }. If done correctly, the original hole #1 contains the final peg. Enjoy.
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Is there an archive such that we (or moderators) can contact old members and urge them back into the swing? This site used to rock with traffic and great riddles/puzzles. Still great material but it's like a ghost town now.
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Sorry, not it. And youre confusing me with plasmid, I believe.
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Spot on!
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What happened to your "I'm not a..." titles, Shakee? Those were so good! An opening guess, in any case.
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Old thread, and masses of discussion, but to simplify - There are 4 equally likely combinations of 2 children: Boy/Boy; Girl/Girl; Boy/Girl; Girl/Boy. The odds of the second child being a girl depend upon how the OP is interpreted and the possible combinations (green) each interpretation allows. 1. They have two kids, [only] one of them is a girl. Boy/Boy Girl/Girl Boy/Girl Girl/Boy - Trick question. In the 2 possible combinations the other child must be a boy. Probability 0. 2. They have two kids, [the first] one of them is a girl. Boy/Boy Girl/Girl Boy/Girl Girl/Boy - There are 2 possible combinations where the first child is a girl. In 1 the other child is too. Probability 1/2. 3. They have two kids, [at least] one of them is a girl. Boy/Boy Girl/Girl Boy/Girl Girl/Boy - Without the Boy/Boy combination 3 remain, in 1 of which the other child is a girl. Probability 1/3.
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I am trying to help my son solve a sequence puzzle. I tried the "read the line" on this one and still can't figure it out. The below is a number puzzle. It should be read left to right, top to bottom. Question 1 What is the next two rows of numbers. Question 2 How was this reached. 1 1 1 2 1 1 2 1 1 1 2 3 1 1 3 1 2 2 1 ? ?
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kristy1992 joined the community
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Jellonz joined the community
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I bite when bitten Smite the smitten Hang the lowly Who die so slowly My eyes request The tougher test So shed your doubts And cast me out
