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arjunsinseo joined the community
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kerum2 joined the community
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No, still not it : ) Though rather easy for you guys.
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BMAD started following Solving a system of functional equations , A taylor series problem.... , One last functional equation and 2 others
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Let F(t)=f(t)/g(t) be a rational function with integer coefficients, assume g(0)=1, then the Taylor expansion of F(t) at 0 has integer coefficients, and more over, these coefficients satisfy a recursion relation of the form c_n+k=a_{k-1}c_{n+k-1}+ ... + a_0c_n (k and all a_i are all fixed integers) for all but finitely many n? (for example try computing a MacLauren series for (1+2x)/(1-x^3)
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Hello. We are devising complex tests to find extremely intelligent individuals. There are well hidden messages inside our videos. Find them and write the solution Good luck. Are You Smart Enough? https://youtu.be/aiT4e4qtekE
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Alternatively,
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(f(x+y)-f(xy))/(3x) = f(y/(3x))-11-y Find f(x) where f(x) is a polynomial.
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Emoji based math puzzle - level hard!
BMAD replied to Solvemoji's question in New Logic/Math Puzzles
I get two possible solutions: 1100 or 76461. Though if we want only positive values for each emoji then my answer of 1100 is the correct one. Though I am treating the fact that like how one row has two emojis of alligators and is different than the other rows, then the eagles being doubled is significant. -
2f(1/x)-f(x)+2f(2/x)-f(x/2) = x, x is defined on the reals except where x =0 find f(x) =
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Solving a system of functional equations
EventHorizon replied to BMAD's question in New Logic/Math Puzzles
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h(f(x)) + g(h(x)) + f(g(x)) = 2x^2 + 11x + 14 f(h(x)) + h(g(x)) + g(f(x)) = 2x^2 - 15x + 66 f(g(x)) = g(f(x)) h(g(x)) - g(h(x)) = -16x + 72 h(f(x)) + f(h(x)) = 2x^2 + 10x + 30 f(x) * g(x) = h(x) - 3x - 40 ----- f(x) = g(x) = h(x) =
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jonson23mack started following MathVerse
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and there it is... of course. Nice solve plasmid my friend. And as expected, another most excellent riddle Shakee.
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Been around your world, I've seen it all, I make a stand, defy the fall. I hold on tight, keep it in, Otherwise unwise cry sin. I may be false or have thick skin, A shot or hit in name my kin.
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Ding ding ding! Winner! Standards are the uprights that hold the crossbar.
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This may be a little over the top, but are you
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Hear the third person almost surrender protection.
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No. Good guess
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Corrupt?
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A car jack? Headed out of the country with unknown internet service. Will check in when I can.
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Option in a broken chalice gone bad.