fabpig Posted July 1, 2012 Report Share Posted July 1, 2012 (edited) or even 2*4*108 So should we now just select 6 random numbers - plus the target? ( that's not a complaint, just a possible natural evolution of the game). It seems that the old format was gettin a bit easy Edited July 1, 2012 by fabpig Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 2, 2012 Report Share Posted July 2, 2012 i say 2 random 2 digits and 4 random 1 digits if thats fine. Quote Link to comment Share on other sites More sharing options...
MikeD Posted July 2, 2012 Author Report Share Posted July 2, 2012 I agree. So 3, 4, 7, 9, 21, 54 477 Quote Link to comment Share on other sites More sharing options...
curr3nt Posted July 2, 2012 Report Share Posted July 2, 2012 54*9-(21/7*4)+3 = 477 I think it is more challenging to have to use all 6 numbers Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 2, 2012 Report Share Posted July 2, 2012 (edited) (54 - (4-3)) x 9 = 477 dang it, curr3nt!!! ^ edit Edited July 2, 2012 by TheCube Quote Link to comment Share on other sites More sharing options...
curr3nt Posted July 2, 2012 Report Share Posted July 2, 2012 You can pick numbers Cubie Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 2, 2012 Report Share Posted July 2, 2012 no, you got the most numbers in the equation you should go. Hey, should we count if all numbers are used? Quote Link to comment Share on other sites More sharing options...
MikeD Posted July 2, 2012 Author Report Share Posted July 2, 2012 So that if someone reaches the total with all the numbers he beats someone who reached the total using only some of the numbers? Quote Link to comment Share on other sites More sharing options...
curr3nt Posted July 2, 2012 Report Share Posted July 2, 2012 (edited) I just think all numbers must be used to reach the total period. Some of the answers are easy if you can just use a few. Trying to make them all work is more challenging. *shrug* You all can do what you want but my future answers I'm going to use all the numbers. So there. 2, 3, 5, 8, 13, 21 ?= 987 --edit-- The count of numbers used might not work because if you got it with say 4 numbers how long would you wait to know it was your turn? Edited July 2, 2012 by curr3nt Quote Link to comment Share on other sites More sharing options...
MikeD Posted July 2, 2012 Author Report Share Posted July 2, 2012 I agree it has been a bit too easy so far. Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 2, 2012 Report Share Posted July 2, 2012 (21)(8*5 + (13 - 3*2)) = 987 Quote Link to comment Share on other sites More sharing options...
MikeD Posted July 8, 2012 Author Report Share Posted July 8, 2012 @TheCube: Cubie you need to post the next set of numbers. @All: Do we agree that we have to use all the numbers? Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 9, 2012 Report Share Posted July 9, 2012 alright 473 4, 2, 9, 1, 84, 14 and yes, use all numbers i say. Quote Link to comment Share on other sites More sharing options...
curr3nt Posted July 9, 2012 Report Share Posted July 9, 2012 84*4+(9+1)*14-2 = 474 Quote Link to comment Share on other sites More sharing options...
plainglazed Posted July 12, 2012 Report Share Posted July 12, 2012 (84-14+9)(4+2)-1=473 am working on the next. that part's harder than the solve. be right back. didnt try to solve this one, just worked backwards from one solution, so it might be easy. or it might be not.... 1, 2, 7, 9, 31, 75 = 369 Quote Link to comment Share on other sites More sharing options...
curr3nt Posted July 13, 2012 Report Share Posted July 13, 2012 75+(31*9)+(2*7)+1 = 369 I prefer to just make up numbers. 1, 3, 5, 7, 11, 13 ?= 444 Quote Link to comment Share on other sites More sharing options...
plainglazed Posted July 15, 2012 Report Share Posted July 15, 2012 (13*3-7+5)(11+1)=444 1,2,3,4,10,11 = 999 Quote Link to comment Share on other sites More sharing options...
MikeD Posted July 15, 2012 Author Report Share Posted July 15, 2012 (11*10+1)*(2+3+4) 3,5,8,9,13,60 = 782 Quote Link to comment Share on other sites More sharing options...
nana77 Posted July 16, 2012 Report Share Posted July 16, 2012 -3*5+8+9+13*60=782 4,5,11,34,8,9 = 258 Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 16, 2012 Report Share Posted July 16, 2012 (34+11+5)(9-4)+8=258 8, 5, 2, 9, 82, 37 = 741 Quote Link to comment Share on other sites More sharing options...
nana77 Posted July 16, 2012 Report Share Posted July 16, 2012 (82+8)*9+5-37*2=741 this one should be a little harder... 5, 9, 8, 7, 56, 37=703 Quote Link to comment Share on other sites More sharing options...
TheCube Posted July 16, 2012 Report Share Posted July 16, 2012 (37)((56+9*8+5)/7)=703 5, 1, 7, 3, 92, 74 = 981 btw, are you Nana7 from Mafiamaniac, Nana77? Quote Link to comment Share on other sites More sharing options...
curr3nt Posted July 16, 2012 Report Share Posted July 16, 2012 (74+92)*(7-1)-(5*3) = 981 6, 7, 8, 9, 10, 42 = 783 Quote Link to comment Share on other sites More sharing options...
nana77 Posted July 16, 2012 Report Share Posted July 16, 2012 (edited) btw, are you Nana7 from Mafiamaniac, Nana77? Yes. My Nana7 account here was lost in the crash months back and I did not feel it worth the trouble of reviving. and Hi Curr, nice to see ya. Edited July 16, 2012 by nana77 Quote Link to comment Share on other sites More sharing options...
nana77 Posted July 16, 2012 Report Share Posted July 16, 2012 (edited) hmm, within 1 point (10+6)*(42+8)-7-9=784 can numbers be combined like 6,7 into 67 or 76? Edited July 16, 2012 by nana77 Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.