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unreality

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Everything posted by unreality

  1. unreality

    Rollo

    talky edit - nvm, beaten to it
  2. unreality

    Rollo

    aerie eerie faery
  3. unreality

    Rollo

    in that case, LEMON also GANJA and CAPER
  4. unreality

    Rollo

    scores: +30 for izzy +18 for t8t8t8 (did i count right?) Unreality - 191 Izzy - 187 Framm - 152 t8t8t8 - 90 Plainglazed - 85 Dawh - 66 Glycereine - 50 Abhisk - 20 Prince Marth - 15 DudleyDude - 10 still behind me, izzy edit added t8t8t8t's points
  5. unreality

    Rollo

    haha. speaking of the score, here it is as of the end of the previous round: Unreality - 191 Izzy - 157 Framm - 152 Plainglazed - 85 t8t8t8 - 72 Dawh - 66 Glycereine - 50 Abhisk - 20 Prince Marth - 15 DudleyDude - 10
  6. unreality

    Rollo

    wow i'm way behind
  7. unreality

    Rollo

    PLIED - 3 TOILS - 1 TAROT removes T of TOILS CZARS removes S of TOILS ***E* removes L of TOILS so from TOILS it's either the O or I PIZZA removes P from PLIED E accounts for 1 of 3 so from PLIED it's 2 of the following: L, I, D. Hence to satisfy both the TOILS and PLIED: it's either: * O and L at same time plus D (because it's o OR middle i) or * I for TOILS, I from PLIED, and either the L or D from PLIED. The first bullet point is impossible becuase O & L can't occupy the same letter. SO it's teh second bullet point. We have enough information to conclude that the middle letter is I, but not enough to know whether it's the L or D from PLIED that joins it so **IE* eedit way behind lol
  8. unreality

    Rollo

    from the logic given in my last post, the second to last letter is E
  9. unreality

    Rollo

    using these: TEMPE - 0 AMBER - 1 EMBER - 1 ELMER - 1 OCCUR - 0 we can _almost_ prove one/two letter/s. (1) AMBER to EMBER retains 1, so it's not A in AMBER or E in EMBER. (2) ELMER also got 1. Not the E as we see in (1). Not the M as we see from TEMPE=0. Thus it's _L_ER. (3) because we know it's _MBER and _L_ER, the 1s can be caused by: (3a) *M*** and either the E or R - but not possible because then AMBER and EMBER would be 2. So this isn't possible (3b) **B** and either the E or R - again not possible for same reason (3c) **B** and *L***, this is possible (3d) either the E or R. (4) OCCUR = 0, so not the R (5) leaving our possibilities as: *LB** or ***E* (6) now CZARS=0. TAROT=0. So if CARES gets higher than 0, it's not because of the C, A or R. And GUESS got zero so it can't be the S. So "CARES" must either get 0 (in which case *LB**) or 1 (in which case ***E*) so i'm guessing: CARES the answer to CARES determines whether I score one or two letters
  10. unreality

    Rollo

    CZARS KAZOO PIZZA AMBER DEPTH
  11. unreality

    nay we merely looked inside of us and saw the Truth
  12. unreality

    Rollo

    on the contrary, the idea came to me when a bunch of us were on at the same time playing all at the same time. So it's possible, and if it's planned before hand too it could get more than just a few
  13. unreality

    Rollo

    yeah let's just do dawh +5, PM +5, glyc +20, framm +31 Unreality - 186 Izzy - 157 Framm - 152 Plainglazed - 85 Dawh - 66 t8t8t8 - 57 Glycereine - 30 Abhisk - 20 Prince Marth - 15 there are always 30 points per round given out to the non-host players (5 per letter and the 5 bonus from getting the final letter). Also has anyone given any thought to the STR thing i posted? and to glycereine: how about MAUVE
  14. unreality

    Rollo

    HIPPY BISON DICER DELVE
  15. unreality

    Rollo

    RIVET ETHER EIGHT
  16. unreality

    I think that might work but it's probably NOT more efficient than the other way. I guess it all depends on that roulette wheel EDIT: nevermind! There's a 50% chance the dial will start in a 2 or 3 position, which creates an endless moratorium
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