wolfgang
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Everything posted by wolfgang
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16 - 36 = 25 - 45 4^2 - (9x4) = 5^2 -(9x5) 4^2 - (9x4) + 81/4 = 5^2 -(9x5) + 81/4 ......by adding 81/4 to both sides (4-9/2)^2 = ( 5-9/2)^2......we can cancel the powers on both sides 4- 9/2 = 5- 9/2............add 9/2 to both sides to get: 4=5 !!! Am I wrong?
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Let X= 0.9999............. then 10X=9.99999.......... 10X- X = 9.99999......... - 0.999999....... 9X = 9 that means: X=1 so 1= 0.999999........ the same is in case of: 1/3+1/3+1/3 =3/3 = 1 but, 1/3 = 0.33333......... so 0.333333......+0.33333.....+0.33333.......= 0.999999....... which is < 1 Am I wrong?
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right..thx
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something has: ch to right,ch to the left and you are in the middle! what is it?
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Thats it...Very good!
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Try to find the missing number :- 10,31,59,97,.........,173 please give your reason....thanks.
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Thank you dear.....
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I wish you all, a very happy new year,may all your wishes come true... God bless you... welcome 2012.... ready... 3.....2.....1......Gooooooooo!!
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Meeeeeeeeeerrrrrrrrry Christmas everyone. Glory to God in the highest, and on earth peace, good will toward men. Jesus love you ALL
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Very good!
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You are FANTASTIC!!!!!
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Well...it seems to be easy.....or it may be hard if you don`t sit at the other side....lol What is next to these combinations? 6L,8SI,LE2,9IE,S6E,hLh,......... note: you need a little bit fantasy...
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Thats right...and you can enter numbers in the grid according to my combination also.
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Thats right!....but according to my method ,I was to weigh 102 and 96gms Then using the scale balance I was to devide the total into two equal parts....each one would be 100 gm. .................. +1........... -3 102............101..........105 96...............95............99 (101+99)/2=100 (105+95)/2=100 Thanks
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which is why we can't weigh a specific mass of marbles, otherwise it would be too easy. @wolfgang, I can easily tell which balance is which when I said (more than 5 gms) that may be true if the smallest one is over 10gm either,so we can not estimate the weight and we shouldn`t. In case of No weights of the digital balances, both of them are calibrated to read (0).
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Keep placing marbles on a given balance till a given weight is to be concidered as one weight. I´ll give you an example of 14 marbles having a total weight of 100 gm:- 5.6gm,6.3gm,7.1gm,6.8gm,8.2gm,5.9gm,8.3gm,7.5gm,9.7gm,9.2gm,6.3gm,7.6gm,6.1gm,and 5.4gm
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Yes...I gave the instructions to a magic square,by giving the squares on X-axes,letters(a,b,c,and d) and giving numbers(1 to 4) to Y-axes squares. now,1d will mean the square for 1, and 4b will indicate where number 2 should be,,,and so on
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Sorry...but how can you measure the 49gm?how can you say that this amount of marbles are 49gm?
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we can obtain ten times 34 out of this sequence .
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?? ..what??
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I agree with "The Rogue"
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Nice try...but you should use all of them....ty
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Dear SMV!....only 2 balances are digital,the third one is a scale balance with two arms.
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If you were asked to weigh exactly 100gm of different sized Marbles(each one of them is more than 5gm), using three balances each one only once,these balances are as follows: one ordinary scale balance,which is accurate. and two analytical balances,each one of them has an error,the first one displays (one)gm more..i.e.,if you put 100gm on it, it will show 101gm.,while the other balance displays (three) gm less,...i.e.,by putting 100 on it ,it will display 97gm.and you don`t know which is which.. How can you weigh 100gm...?
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Thank you Dear...I am so glad to hear this....sometimes,the situation is not so complex as we immagine!...take it easier....!!!
