plasmid

Maybe something less ultimate

Nah, it's pretty straightforward with a moderate amount of logic-ing. I'm surprised it hasn't been solved yet, unless the issue lies in understanding what the question is really asking for.

Right on! I would count either that one, or since they might not be commonplace to some people...

Barber's scissors is a pretty good fit. But I'm looking for something that's more commonly associated with perching in a line and flocking with its kind.

IDK, I'm just a biologist It doesn't have anything to do with the fact that any two-color coloring of all possible lines connecting the vertices of a hexagon (without any three colinear points) must create a monochromatic triangle, at least as far as I can tell. And there's probably more to the theory than just that. But for this case, we're told the color of the bowling pins' stripes, not lines connecting them, and they sit in a hexagonal tiling with lots of colinearity and every angle being a multiple of 60 degrees.

I'll go with

Not peas, I can drop stuff that'll make you more splendid than them.

Why thank you, Shakee. I learn by watching the best. Not a feather -- the "I" in this riddle has a curved beak and sheds the droppings, and isn't an eagle or anything too similar.

I perch in a line And flock with my kind Behold as my wings are extended By curve of my beak Are smoothened and sleek Relaxing among the ascended My droppings don’t dread Evading your head They won't splatter, but make you quite splendid

Moving to the other side from my previous answer... Edit: guess I was a day late and a dollar short. Good riddle, Shakee, and nice solve, Thalia

I was thinking of but I also like Wilson's answer with the "lighter than a feather" line (although that clue might still apply to my answer in my case =p)

I was thinking that 5) The Chilean, who is not next door but one to the Belgian... means that there's one pitch between the Chilean and the Belgian. If st3v3n80 is able to ask the friend who gave him the problem these clarification questions, maybe we could sort it out.

I'm coming up with an almost complete solution, but I have ambiguity on who prefers letterbox or virtual caches, which I think could belong to either of two people.

Bob, who's a fairly bright guy, went out to the bowling alley with his buddies. They noticed that some of the bowling pins had the typical red stripes and all of the others had black stripes instead. At one point after a new set of 10 pins were laid down, Bob commented that there were no equilateral triangles formed by pins with the same color stripes. How many beers did Bob have by that point? Provide a proof.

Trying to think like a homeroom student...

I was thinking the same as Thalia. Let's see if this works. @plainglazed @Wilson @DudleyDude @fabpig Master Shakee hath returned.

I agree with Flamebirde's answer. But I would add a bit more to it.

I'll count being in any way confused for Shakee as high praise. As for this one

Pretty sure it's one of these

Cats tend to be sort of lazy by nature, so that's my excuse. But to kick things off

Yes, and this has got to be among the most counter-intuitive properties of infinity that I know of.

Good, but now for the kicker. There's a reason I didn't specify the order in which I pulled out the rugs in the OP. After I finished pulling out every rug and walking the pattern forever, I went back and picked up all my rugs. Then instead of alternating odd-gons and 4x-gons, I placed two 4x-gons in a row before placing the next odd-gon. I still turned the same direction on every rug that I did before: still clockwise on every odd-gon and counterclockwise on every 4x-gon, so in the pattern 4-gon, 8-gon, 3-gon, 12-gon, 16-gon, 5-gon, 20-gon, 24-gon, 7-gon, 28-gon, 32-gon with clockwise turns on blue and counterclockwise on red. After that second forever, which way was I facing?

Clarification: when I walked the odd numbered N-gons I always turned clockwise. When I walked the multiple of 4-gons I always turned counterclockwise. For now, suppose I always alternated between an odd-gon and a 4x-gon without bothering to keep edge number monotonically increasing. So 3-gon, 4-gon, 5-gon, 8-gon, 7-gon, 12-gon, 9-gon, etc with clockwise turns on blue and counterclockwise on red. (Otherwise, yeah, it would be a mess.)

I once stood on a Cartesian plane at (0, 0) facing north (along the positive y-axis). I pulled out a rug in the shape of a regular triangle (which I call a 3-gon) and set it on the plane with one vertex at my feet at (0, 0) and with the center in the direction I was facing along the y-axis. I then started walking forward on the rug until I got to the center of the 3-gon, at which point I stopped and turned clockwise until I was facing a vertex, and I walked to that vertex of the 3-gon. Then I pulled out a rug in the shape of a square (which I call a 4-gon), put it with one vertex at my feet and with the center straight ahead of my current view (after that previous clockwise turn). I walked to the center of the 4-gon and then turned counterclockwise (instead of clockwise like on the odd-numbered N-gon rug), and started walking again as soon as I was facing a new vertex of the 4-gon. I kept repeating that for every odd numbered N-gon and every multiple of 4-gon. Which way was I facing after I did that forever?