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I wish I didn't have to Invite Wives And Husbands From Canada.

That was so unexpected... I guess I should have anticipated it... I knew I should have expected it...

I wish I didn't have to inspect weiners at home freaking coming

Hi my friends...I`ve prepared a nice puzzle to you.. Here we go:- Cut 9 pieces of paper,write a number on each one of them,from 1 to 9,put them in a pot,put the pot on a table. Your aim is to arrenge these numbers on the table in this order: 123456789 according to the following rules: 1- you can choose any number to be the first number, and put it on the table.( for example I choose number 4). 2-take a second number and compare it with the number on the table, if.. 2nd>1st....put it to the left. if 2nd<1st...put it to the right.( in my example, if I choose 7...I`ll get 74.....but if I choose 3.....will be 43). 3-now whenever you have an even amount of numbers on the table( two numbers,4,6,or 8), you should insert any number you want between them,just in the middle.(in my example, if I want to choose 5,so I should put it in the middle to get 754,,,or 453). 4- you are allowed to take any number from the table and put it back in your pot. but to put any number again on the table,you should follow the rules. 5-to put the 4th number, you should compare it with the middle number( in my example...with number 5), if the choosen number>than the middle number....put it to the left, if the choosen number < than the middle number...put it to the right.(in my example, if I choose number 9,,so 9>5...I`ll get 9754,,,or 9453). 6-as in step 3. 7-whenever you have an odd amount of numbers on the table(one number,3,5,7,or 9),you should compare your choosen number with the middle number, if your choosen number>the middle number....put it to the left. if your choosen number<than the middle number.....put it to the right. Have a nice time

Wish I had the story-telling ability of the other contributers, but this has time, indicated whenever Fabpig says the last rights.

Orly? Bwahahaha! You know what's even better about this?? I am the only one who hasn't actually been here for any of it, and i'm leading

I know I said, that I wanted RG3, but only getting him is ridiculous...

My apologies for not using a Spoiler but I think we are all playing together against the Witch and trying to reformat this inside a spoiler would be a huge pain. This is what I have so far. Nothing I can make much sense of, but maybe will help everyone else. The nth term in sequence K is: (49 - n)/[2|3] where '[2|3]' means 'either 2 or 3', but I haven't yet figured out when to use 2 instead of 3 or vice versa. Similarly, the nth term in sequence H is: n*[1|2|3|4] Rewriting the sequences with the variable choices yeids: H: 3,2,2,2,3,3,4,1,3,2,3,1,2,3,1 K: 2,2,3,3,3,2,3,2,3,2,3,3,2,2,2 I'm guessing that we need to figure out the rules behind the 2 sequences and extend them out far enough to find the corresponding pairs that K and H quote at the very end (112,21), (93,9), (48,0.5), (84,14), (18,10.3), (84,7) and that the values of n for each entry will end up corresponding to a 6 letter word. Since the H sequence involved [1|2|3|4], I decided to try that as well for the K sequence. I'm still not sure how to decide which multiplier/divisor is used, so I opened a spreadsheet and calculated all 4 possible H and K sequence numbers for n=1:48. I then looked for n's where both the final values quoted by H and K were existing for that value of n. That yielded the following sequence 28,31,48,21,18, 28. I still don't know if this sequence is significant nor how to convert it to a word.