Jump to content
BrainDen.com - Brain Teasers
  • 0

Particle detectors


TimeSpaceLightForce
 Share

Question

22 answers to this question

Recommended Posts

  • 0
  On 4/16/2013 at 6:37 AM, bonanova said:

  Reveal hidden contents
Is the opening a square that is 1 meter on a side?

Can the opening take the shape of the detector?

My guess is a both the opening and the detector should be circles, but it's not clear that both shapes are variable.

  Reveal hidden contents

the buried cube is 1x1x1m metal box without cover on top

Link to comment
Share on other sites

  • 0
  On 4/17/2013 at 10:54 AM, TimeSpaceLightForce said:

  On 4/16/2013 at 9:23 PM, Rob_Gandy said:

  Reveal hidden contents

you made the detector a square along the diagonal of the cube?

That is 1 x 1 m only because the side is 1 m, there is a larger square that will fit in the cube.

  Reveal hidden contents

The detector would be sqrt(2) x sqrt(2)

Link to comment
Share on other sites

  • 0
  On 4/17/2013 at 6:51 PM, Rob_Gandy said:

  On 4/17/2013 at 10:54 AM, TimeSpaceLightForce said:

  On 4/16/2013 at 9:23 PM, Rob_Gandy said:

  Reveal hidden contents

you made the detector a square along the diagonal of the cube?

That is 1 x 1 m only because the side is 1 m, there is a larger square that will fit in the cube.

  Reveal hidden contents

The detector would be sqrt(2) x sqrt(2)

Oops ignore that...

Link to comment
Share on other sites

  • 0

I strongly dislike AutoCAD :D so many rough memories

  On 4/18/2013 at 3:42 AM, TimeSpaceLightForce said:

  On 4/18/2013 at 2:44 AM, BMAD said:

  On 4/18/2013 at 2:14 AM, TimeSpaceLightForce said:

  Reveal hidden contents

which is larger..the biggest square that fits in a cube or the biggest circle that fits in a cube?

  Reveal hidden contents

Prince Rupert

  Reveal hidden contents

AutoCAD

Link to comment
Share on other sites

  • 0
  On 4/22/2013 at 6:54 AM, bonanova said:

  Reveal hidden contents
I didn't say, but it seems obvious that

if you make the detector a circle, you throw away area needlessly.

The constraint for a circle to fit does not preclude adding corners to it.

So a circular shape is always suboptimal.

  Reveal hidden contents

that is, if the circle is inside the square..

Link to comment
Share on other sites

  • 0
  On 4/22/2013 at 9:53 AM, TimeSpaceLightForce said:

  On 4/22/2013 at 6:54 AM, bonanova said:

  Reveal hidden contents
I didn't say, but it seems obvious that

if you make the detector a circle, you throw away area needlessly.

The constraint for a circle to fit does not preclude adding corners to it.

So a circular shape is always suboptimal.

  Reveal hidden contents

that is, if the circle is inside the square..

assures the detector is inside a cube.

Link to comment
Share on other sites

  • 0
  On 4/24/2013 at 4:26 PM, TimeSpaceLightForce said:

ok, why is a circular detector bigger than the square detector ?

Circles aren't bigger or smaller than squares until constraints are added.

  1. If the constraint is a given perimeter, circles are bigger (area wise)
  2. If the constraint is maximum and minimum values of x and y, then squares are bigger.

The present constraints are of the second type.

  • Upvote 1
  • Downvote 1
Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Answer this question...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

 Share

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...