BMAD 62 Report post Posted February 25, 2013 The towns of Alpha, Beta, and Gamma are equidistant from each other. If a car is three miles from Alpha and four miles from Beta, what is the maximum possible distance of the car from Gamma? Assume the land is flat. Share this post Link to post Share on other sites

0 k-man 26 Report post Posted February 25, 2013 (edited) I'm finding it hard to believe, so I'm second guessing myself that I messed up somewhere in the calculations, but the answer I got is 7. It occurs when the angle formed between Alpha,Car,Beta is 120 degrees and the distance between the towns is sqrt(37). Edited February 25, 2013 by k-man Share this post Link to post Share on other sites

0 bonanova 77 Report post Posted February 25, 2013 Don't have pencil and paper handy. It occurs to me the towns are 1 mile apart and the car lies on a line joining alpha and beta. Its distance from gamma is 3.5 miles along that line, say north, and the height of the triangle say to the east. Apply Pythagoras. Share this post Link to post Share on other sites

0 BMAD 62 Report post Posted February 25, 2013 (edited) Don't have pencil and paper handy. It occurs to me the towns are 1 mile apart and the car lies on a line joining alpha and beta. Its distance from gamma is 3.5 miles along that line, say north, and the height of the triangle say to the east. Apply Pythagoras. They don't have to be 1 mile apart and i got 3.61 when they were 1 mile apart Edited February 25, 2013 by BMAD Share this post Link to post Share on other sites

0 CaptainEd 19 Report post Posted February 25, 2013 If the side of the equilateral triangle were 5, and the car formed a 3,4,5 triangle with Alpha and Beta, then the car would be 6.77 from Gamma. It isn't as good to put the car on the line between alpha and beta, with a side of 7, as the car would be 6.01 from gamma. Share this post Link to post Share on other sites

0 BMAD 62 Report post Posted February 25, 2013 If the side of the equilateral triangle were 5, and the car formed a 3,4,5 triangle with Alpha and Beta, then the car would be 6.77 from Gamma. It isn't as good to put the car on the line between alpha and beta, with a side of 7, as the car would be 6.01 from gamma. That is a nice improvement CaptainEd but still even that isn't the maximum distance. Share this post Link to post Share on other sites

0 BMAD 62 Report post Posted February 25, 2013 I'm finding it hard to believe, so I'm second guessing myself that I messed up somewhere in the calculations, but the answer I got is 7. It occurs when the angle formed between Alpha,Car,Beta is 120 degrees and the distance between the towns is sqrt(37). I found the distance between the towns to be the sqrt(36) or 6. Share this post Link to post Share on other sites

0 k-man 26 Report post Posted February 25, 2013 (edited) ...and sqrt(37) is the correct distance between the towns. For any a and b, where a is the distance from the car to Alpha and b is the distance from the car to Beta, the maximum distance from the car to Gamma is a+b and is achieved when the angle formed by the lines connecting the car with Alpha and Beta is equal 120 degrees. Applying the law of cosines with 120 degree angle we get the distance between towns = sqrt( 3^{2 }+ 4^{2 }- 2 * 3 * 4 * cos(pi/3) ) = sqrt(37). Edited February 25, 2013 by k-man Share this post Link to post Share on other sites

0 BMAD 62 Report post Posted February 26, 2013 ...and sqrt(37) is the correct distance between the towns. For any a and b, where a is the distance from the car to Alpha and b is the distance from the car to Beta, the maximum distance from the car to Gamma is a+b and is achieved when the angle formed by the lines connecting the car with Alpha and Beta is equal 120 degrees. Applying the law of cosines with 120 degree angle we get the distance between towns = sqrt( 3^{2 }+ 4^{2 }- 2 * 3 * 4 * cos(pi/3) ) = sqrt(37). three towns.png I stand corrected. I didn't catch that i rounded :b Share this post Link to post Share on other sites

0 Debasis 0 Report post Posted February 26, 2013 (edited) gamma should be (3^1/2)3.5/2 miles apart if we draw two circle with center alpha and radius 3miles and beta with radius miles we see that gamma will see that they will form an equilateral triangle with side 3.5 iles applying pythagoras theorem we will get the maximum distance.... now i found out that i am wrong .....Happens! Edited February 26, 2013 by Debasis Share this post Link to post Share on other sites

0 Debasis 0 Report post Posted February 26, 2013 ...and sqrt(37) is the correct distance between the towns. For any a and b, where a is the distance from the car to Alpha and b is the distance from the car to Beta, the maximum distance from the car to Gamma is a+b and is achieved when the angle formed by the lines connecting the car with Alpha and Beta is equal 120 degrees. Applying the law of cosines with 120 degree angle we get the distance between towns = sqrt( 3^{2 }+ 4^{2 }- 2 * 3 * 4 * cos(pi/3) ) = sqrt(37). three towns.png hey man can you tell me how you worked out that the angle between alpha and beta should be 120 degrees .i just acant understand..Thanks Share this post Link to post Share on other sites

0 k-man 26 Report post Posted February 26, 2013 ...and sqrt(37) is the correct distance between the towns. For any a and b, where a is the distance from the car to Alpha and b is the distance from the car to Beta, the maximum distance from the car to Gamma is a+b and is achieved when the angle formed by the lines connecting the car with Alpha and Beta is equal 120 degrees. Applying the law of cosines with 120 degree angle we get the distance between towns = sqrt( 3^{2 }+ 4^{2 }- 2 * 3 * 4 * cos(pi/3) ) = sqrt(37). three towns.png hey man can you tell me how you worked out that the angle between alpha and beta should be 120 degrees .i just acant understand..Thanks I knew someone would ask that question It was a little messy and maybe not in the most efficient way, but... I used the laws of cosines and sines to express the distance to Gamma as a function of the angle between Alpha and Beta. Then I to took a derivative of that function to find the local maxima and found it to be at 120 degrees. If I have more time later, I may post the complete solution Share this post Link to post Share on other sites

0 Debasis 0 Report post Posted February 27, 2013 ...and sqrt(37) is the correct distance between the towns. For any a and b, where a is the distance from the car to Alpha and b is the distance from the car to Beta, the maximum distance from the car to Gamma is a+b and is achieved when the angle formed by the lines connecting the car with Alpha and Beta is equal 120 degrees. Applying the law of cosines with 120 degree angle we get the distance between towns = sqrt( 3^{2 }+ 4^{2 }- 2 * 3 * 4 * cos(pi/3) ) = sqrt(37). three towns.png hey man can you tell me how you worked out that the angle between alpha and beta should be 120 degrees .i just acant understand..Thanks I knew someone would ask that question It was a little messy and maybe not in the most efficient way, but... I used the laws of cosines and sines to express the distance to Gamma as a function of the angle between Alpha and Beta. Then I to took a derivative of that function to find the local maxima and found it to be at 120 degrees. If I have more time later, I may post the complete solution thanks! Share this post Link to post Share on other sites

The towns of Alpha, Beta, and Gamma are equidistant from each other. If a car is three miles from Alpha and four miles from Beta, what is the maximum possible distance of the car from Gamma? Assume the land is flat.

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