I haven't been able to figure out the solution to this, so I thought I'd see if anyone out there can help!
Start with a standard deck of 52 playing cards, face down, in a random order. One at a time, turn the cards over. As you do so, count out loud in the following order: ace, 2, 3, 4, all the way up to jack, queen, king, ace, 2, 3, 4, all the way up to king...four times. That is, you count in order while you flip over cards.
The question is: What is the probability that you can make it all the way through the 52-card deck WITHOUT the flipped card matching the spoken card?
For example, let's say the first ten cards in the deck are K, 6, 8, Q, Q, J, 9, 8, 10, 3. You begin by flipping the first card, a king, and saying "Ace." The next card flipped is 6, and you say "two." Third card is 8, and you say "three." Fourth is queen, you say "four." Keep going. However, when you get to the 8th card, you flip over an 8 and say "eight." Since the flipped card and the spoken card are the same, you lose.
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I haven't been able to figure out the solution to this, so I thought I'd see if anyone out there can help!
Start with a standard deck of 52 playing cards, face down, in a random order. One at a time, turn the cards over. As you do so, count out loud in the following order: ace, 2, 3, 4, all the way up to jack, queen, king, ace, 2, 3, 4, all the way up to king...four times. That is, you count in order while you flip over cards.
The question is: What is the probability that you can make it all the way through the 52-card deck WITHOUT the flipped card matching the spoken card?
For example, let's say the first ten cards in the deck are K, 6, 8, Q, Q, J, 9, 8, 10, 3. You begin by flipping the first card, a king, and saying "Ace." The next card flipped is 6, and you say "two." Third card is 8, and you say "three." Fourth is queen, you say "four." Keep going. However, when you get to the 8th card, you flip over an 8 and say "eight." Since the flipped card and the spoken card are the same, you lose.
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