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# Rollo

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```_ _ _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)```

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Sorry, Mikey. I just got mugged by a rampant Brainything.

NEVER

What just happen? I go to work this morning just finished my round, and waiting for fabpig to start his. I log on now to find that its finished???

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```_ _ _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)```

decor

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```_ _ _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1) ```

santa

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```_ _ _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)```

..I don't like my word anymore.

panda

panda

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```_ _ _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)```

palor

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```_ _ _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)

palor - (2)```

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second letter is A

palor is 2, 1 is from the o

the final R is not the other 1 cuz color only had 1 (its o)

the middle L is not the other 1 cuz of oiler=0

either the P or A has to be the letter. Now if it was P, panda's 1 would be due to the P and that would make _ANDA all zeroes for a non-P underscore, making SANTA =1 impossible, because _AN_A is identical to PANDA, the second to last letter is already O. So if the first letter were P (and we know the second to last letter is O) then we know that of PANDA, the P is the scorer, hence it's not the _ANTA in SANTA, it has to be S. But a letter cannot be S and P at the same time.

Proof by contradiction - the second letter is A

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_A_O_

A must be the second letter because both SANTA and PANDA have 1 correct letter, and the 4th letter is already taken by O. So the correct letter must be _A_O_ or __NO_. Since PALOR has 2 correct letters, one of which is the O and we know R is not the last letter from the original guesses, 2nd letter must be A.

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Unreality + 5.

```_ A _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)

palor - (2)```

TWIST

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```_ A _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)

palor - (2)

twist - (0)```

favor

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```_ A _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)

palor - (2)

twist - (0)

favor - (2)```

kazoo

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```_ A _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)

palor - (2)

twist - (0)

favor - (2)

kazoo - (3)```

kazow!!!!

RACES

RODEO

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```_ A _ O _

color - (1)

codes - (0)

colon - (1)

oiler - (0)

bloat - (0)

above - (0)

decor - (1)

santa - (1)

panda - (1)

palor - (2)

twist - (0)

favor - (2)

kazoo - (3)

kazow - (2)

races - (1)

rodeo - (1)```

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as i expected. Last letter is O

races has 1 from the a, so R is not first letter. Hence "rodes" if it were a word would be a 0 because of "codes = 0" and R is not first letter.

So rodes -> rodeo goes from 0 to 1, only thing changing is switching to O in the last spot

so last letter is O

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