AVAST
EVADE = 2, with E proven 5th, must mean either E is 1st or V is 2nd, but not both, since SCARE =1 rules out A and READY =0 rules out D.
For AVAST, only V can be due to ADORE = 1, READY = 0, MOUSY =0 and E is 5th rules out A, A, S, T respectively.
Therefore, If AVAST = 1, then V is 2nd. If AVAST = 0, E is 1st as only possible letter left FROM EVADE = 2