Pickett

Well, he mentioned that there were still unanswered questions..and that figuring them out would be key. So, while I agree the capital letters are probably important, I think figuring out the questions is a good idea... Those are some of the questions that I think may help in solving this...

So, is this anagram completely jumbled? or is each word its own anagram? I would guess that it's completely jumbled. If that's the case, are the word lengths at least correct?

So, my dad told me this little problem quite a few years ago (when I was 8 or so...took me years to figure out how to solve it). It has always stuck with me because of that...so it's just a straightforward math problem, but it's a fun one: There is an alley. In this alley there is a 20ft ladder and a 30ft ladder. These ladders cross over the alley from the ground to the opposite building. They cross each other 10ft above the ground. How wide is the alley? Here's a simple drawing to represent this problem:

oops, sorry for the double post...browser messed up when submitting didn't think it posted.

Well, since I solved your number sequence #4, the second sequence was pretty simple for me:

Well, finding the next number is really dependent on your rounding. it's almost easier just to give the formula used for the sequence:

That only leaves one more: NUNS

I've seen all of these "proofs" being added recently for 2 = 0, 1 < 0, etc, etc...so I figured I'd add my two proofs for 2 = 1, and proof that magic exists... I apologize if these have already been posted...I haven't seen them yet though, so I thought I would put them up. These aren't difficult, and I fully expect them to be solved very quickly, but they're fun. This first one is the golden oldie (I learned this one quite a few years ago and still like it): let a = b a2 = ab (multiply both sides by a) a2 - b2 = ab - b2(subtract b2 from both sides) (a + b)(a - b) = b(a - b) (factor) (a + b) = b (divide both sides by (a - b) ) b + b = b (substitution) 2b = b 2 = 1 Then this following one uses calculus (fun one at first when learning calculus): x = 1 + 1 + ... + 1 (x times) x2 = x + x + ... + x (multiply through by x) 2x dx = (1 + 1 + ... + 1) dx (take deriviative of both sides) 2x = (1 + 1 + ... + 1) 2x = x 2 = 1 and my last one is to show that something TRULY can come from nothing: 0 = 0 + 0 + 0 + ... 0 = (1 - 1) + (1 - 1) + (1 - 1) + ... (since 0 = 1 - 1) 0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + ... (associative law of addition) 0 = 1 + 0 + 0 + 0 + ... (since -1 + 1 = 0) 0 = 1 So, as if by magic something appeared out of nothing! YAY!

I figured this one out last night actually... Good sequence riddle. I liked it. I'm amazed I actually figured it out...

This is my first post on Brainden!!