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There is a stack of Bingo Cards. It is required to find a specific card having the number arrangement as hinted in the following clues: [1] On the cards, there are five columns (named hereafter as A, B, C, D, & E) and five rows (named hereafter as J, K, L, M, & N). [2] Column 'A' contains numbers 1 through 15. [3] Column 'B' contains numbers 16 through 30. [4] Column 'C' contains numbers 31 through 45. [5] Column 'D' contains numbers 46 through 60. [6] Column 'E' contains numbers 61 through 75. [7] Center space 'CL' (a place in column C and row L) is free space i.e. contains no number. [8] In row 'J', each numeral (0 through 9) appears only once; e.g. if there is number 43 at space DJ, then at other spaces in this row, there would be no number containing numeral 3 & 4. [9] In row M, sum of all numbers is a perfect square. [10] Row N contains the smallest number in each column. [11] Each row contains only one '2-digit Prime Number'. [12] In column C, difference of lowest to highest number is 8. [13] In column D, each number has digit at 10th place smaller than the digit at unit place. [14] In column E each number is an odd number. [15] In only one column, the numbers are in descending order from top to bottom. [16] In each column, there is only one numeral that appears two times. [17] In each column, the sum of numbers shares a single common prime factor. [18] On the bingo card, numeral 5 appears only once. [19] The sum of the numbers in each diagonal is an odd number. [20]The product of numbers at spaces AL & EL has a unit digit 2. [21] The product of numbers at spaces BL & DL has a unit digit 4.

??? I understood your phone....

It/he/she traveled back in time to warn us... that . . . . . that . . . . . .that . . . . . . tacos . . . . . . . . are good.

Well, if there were infante parallel universes, where different events happen. Then it could be said that the world will end, in some of them, this year.

What most people don't realize is the Mayan calendar is ... cyclical! When you get to the end, you go back to the beginning. So when the Mayan long-count & galactic day calendars coincide to "end" on Dec 21 2012, it's like New Year's Eve for the next 5126 years. (So we should throw one heck of a party, yes? ) Thalia, just to clarify: The Mayan calendar didn't have to take into account leap years. It's actually more specific than the Gregorian calendar (that most of the world uses) which has to have leap years. So saying the Mayan calendar was "wrong" because it didn't have leap years is incorrect. It was the people doing the math to calculate the end of the long-count cycle who didn't take into account leap years & the adjustments made to our calendar cycle over time. Of course, there's also the thought that the original start date of the cycle could have been mis-interpreted, and we may have already passed the into the new cycle ... as much as a decade or possibly even a century ago. Or that it's actually next year or two years away from now. *shrug* At any rate, I'm sure enough that the world isn't ending just because I have to buy a new calendar. I do that every year anyway. (Now, world ending because some idiot decides it'd be a grand idea to declare nuclear war - I can see that happening anytime.)