TimeSpaceLightForce Posted April 23, 2018 Report Share Posted April 23, 2018 (edited) What is the least number of illegal chess moves that would result in such position as shown? Edited April 23, 2018 by TimeSpaceLightForce Quote Link to comment Share on other sites More sharing options...
3 DejMar Posted April 24, 2018 Report Share Posted April 24, 2018 Spoiler Zero. No illegal moves need be made. It is possible that the white pieces began at the top. Two pawns on each side advanced to permit each individual piece to move in legal fashion out of their starting places to their mirrored locations, that is other than the King and Queen which would swap their final mirrored positions. No captures needed to be made, and each King can avoid moving into check while it journeys to its "final" locations. Finally, the remaining pawns may be advanced to their "final" positions. What might be asked is what are the minimum number of legal moves to arrive at the position? If given that only pawns were moved, all captures were removed, no new pieces were added to the board, and the physical laws were not teased, then the minimum number of illegal moves would be eight. Eight of the pawn could have simply been "hopped" over the pawns into their "final" locations. Quote Link to comment Share on other sites More sharing options...
0 Molly Mae Posted April 23, 2018 Report Share Posted April 23, 2018 (edited) 2 hours ago, TimeSpaceLightForce said: What is the least number of illegal chess moves that would result in such position as shown? Assuming a "move" is moving a single piece and not "swapping two pieces": Eight. Eight of the pawns can make it to their current square without illegal moves. The other 8 must illegally hop or teleport to another space. I guess I could notate it out to make sure the answer isn't nine (where the other illegal move would be passing). But 8. Actually, 8 for sure, since the king on either side can triangulate to lose a tempo, if necessary. 0 if we're playing bughouse. Edited April 23, 2018 by Molly Mae Quote Link to comment Share on other sites More sharing options...
0 rocdocmac Posted April 24, 2018 Report Share Posted April 24, 2018 (edited) Spoiler 16 (?) 8 white hops and 8 black hops. Edited April 24, 2018 by rocdocmac Quote Link to comment Share on other sites More sharing options...
0 TimeSpaceLightForce Posted April 24, 2018 Author Report Share Posted April 24, 2018 Spoiler 2 hours ago, DejMar said: Hide contents Zero. No illegal moves need be made. It is possible that the white pieces began at the top. Two pawns on each side advanced to permit each individual piece to move in legal fashion out of their starting places to their mirrored locations, that is other than the King and Queen which would swap their final mirrored positions. No captures needed to be made, and each King can avoid moving into check while it journeys to its "final" locations. Finally, the remaining pawns may be advanced to their "final" positions. What might be asked is what are the minimum number of legal moves to arrive at the position? If given that only pawns were moved, all captures were removed, no new pieces were added to the board, and the physical laws were not teased, then the minimum number of illegal moves would be eight. Eight of the pawn could have simply been "hopped" over the pawns into their "final" locations. What might be the minimum number of legal moves to arrive at the position? Start by exchanging the rooks and knights ( i.e. 20 moves for both players then 20 moves more) Quote Link to comment Share on other sites More sharing options...
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TimeSpaceLightForce
What is the least number of illegal chess moves that would result in such position as shown?
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