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rocdocmac

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Everything posted by rocdocmac

  1. Having a stab at this to get the ball rolling ... Jane Cramer Janice Carter Jack Clark Jasper Clayton Jim Carver
  2. Also thought so, but no! It's in fact 13! Sticking to the method used to generate the next number, of course. But this is where the sequence stops. One can't use the resulting 13-digit number to determine the next one.
  3. The five polyominoes chosen with just a single example ...
  4. I wish to point out a trivial mistake in my OP ... The value at position C10 (1223) and the one at J11 (1226) have inadvertently not been swapped before posting, So both these values are in their correct placings. This means that only 14 swaps need to be done. No extra cycles, all straightforward X ↔ Y (one exchange per number with another).
  5. In the ten numerical sequences below, three numbers from each sequence have been moved to another sequence, i.e. 15 numbers have been swapped. Which 15 pairs of numbers should be exchanged to make each of the sequences follow a regular pattern? (A) 37, 85, 148, 232, 333, 442, 589, 744, 917, 1108, 1317, 1544 (B) 42, 84, 144, 219, 310, 417, 537, 679, 834, 1005, 1208, 1395 (C) 44, 95, 166, 253, 368, 493, 650, 821, 1012, 1223, 1454, 1705 (D) 70, 122, 189, 271, 366, 475, 598, 735, 890, 1051, 1230, 1423 (E) 123, 181, 252, 335, 430, 540, 656, 787, 930, 1085, 1283, 1431 (F) 149, 209, 280, 361, 452, 553, 691, 785, 916, 1057, 1192, 1369 (G) 160, 190, 220, 253, 288, 325, 364, 406, 448, 499, 540, 589 (H) 253, 320, 395, 478, 569, 666, 775, 886, 1013, 1144, 1252, 1430 (I) 257, 300, 351, 405, 465, 528, 595, 668, 741, 820, 903, 990 (J) 306, 371, 452, 519, 602, 664, 786, 887, 994, 1107, 1226, 1351 Example In the two sequences below, 48 and 52 should be swapped to make sense (A5 ↔ B4). (A) 20, 25, 32, 41, 48, 65. 80 (B) 15, 24, 35, 52, 63, 80, 99
  6. Phil1882 is right ... there is a discrepancy. The 6th term may possibly be 532 901 * 532 901 + 1 = 283 982 410 001.
  7. You've got all of them correct! Kindly tell all Braindenners how you managed that. My explanation to follow after that (if necessary).
  8. @mtngoat @SamSam11
  9. @mtngoat ... @flamebirde @Brainden
  10. Flamebirde ... there's an additional score (7/10) by Jim56 to consider!
  11. Intentially done so. Player VI could not make up his mind with two positions and duplicated one of the letters! The solution indeed has 10 different letters. Jim56, your score is 7/10.
  12. I once participated in a test where the answers had to be chosen from the first 10 letters of the alphabet (A-J). Not bothered too much about the solution, I merely answered by matching the letters with numbers 1 to 10 in strict alphabetical order. I managed a score of only 2/10! I showed the result to a friend of mine who bettered the score to 5/10 with his attempt. The same test was passed on to five more people, each who was entitled to view all previous results. All of them scored 7/10, meaning that no one was spot on. (1) What is the probability that the next person will get 10/10 on his first try? (2) If you were to submit a solution as contestant № VIII, which letters would you enter to ensure that you obtain full marks? Here’s the score sheet for attempts I to VII:
  13. Not a bad attempt at all!
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