Hard riddle

[Mat961]

Please help me solve this riddle. The answer is 30 but i dont know the solution.

[flamebirde]

Spoiler

I think the first digit is the absolute value of the left two numbers subtracted from each other. 3-4=-1 and the absolute value is 1; 4-1=3; 2-3=-1 and the absolute value is 1. That does give us the 3 in 30. But then I have no clue...

 

[vrt]

I don't know about the numbers in the corners, but 12+20=32, 32-18=14, and 14+16=30. So the numbers are alternating adding and subtracting decreasing multiples of 2. Hope this helps!

[rocdocmac]

The equation TL*BR*9 + TR*2 - BL*52 (where TL = top left digit, BR = bottom right digit, etc.) will give the three known answers.

Thus

3*8*9 + 2*2 - 4*52 = 216 + 4 - 208 = 12

4*2*9 + 6*2 - 1*52 = 72 +12 - 52 = 32

2*9*9 + 4*2 - 3*52 = 162 + 8 -156 = 14

But then a total of "30" is not obtained with the unknown ... so I don't know whether that figure was a thumb suck or not!

5*6*9 + 3*2 - 3*52 = 270 + 6 - 104 = 172

Possibly still a valid answer, though.

 

 

[rocdocmac]

Answer:

((Bottom Right/Bottom Left)+Top Right)*Top Left, i.e. for 4th diagram ...

(6/2 + 3)*5 = 30

Edited March 23, 2017 by rocdocmac
No abbreviations

[wolfgang]

(BR / BL +UR) UL

Thus...

(8/4 +2) 3= 12

(2/1 + 6) 4= 32

(9/3 +4) 2= 14

and for the last one..

(6/2 +3) 5 = 30