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Mat961

Hard riddle

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I think the first digit is the absolute value of the left two numbers subtracted from each other. 3-4=-1 and the absolute value is 1; 4-1=3; 2-3=-1 and the absolute value is 1. That does give us the 3 in 30. But then I have no clue...

 

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I don't know about the numbers in the corners, but 12+20=32, 32-18=14, and 14+16=30. So the numbers are alternating adding and subtracting decreasing multiples of 2. Hope this helps!

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The equation TL*BR*9 + TR*2 - BL*52 (where TL = top left digit, BR = bottom right digit, etc.) will give the three known answers.

Thus

3*8*9 + 2*2 - 4*52 = 216 + 4 - 208 = 12

4*2*9 + 6*2 - 1*52 = 72 +12 - 52 = 32

2*9*9 + 4*2 - 3*52 = 162 + 8 -156 = 14

But then a total of "30" is not obtained with the unknown ... so I don't know whether that figure was a thumb suck or not!

5*6*9 + 3*2 - 3*52 = 270 + 6 - 104 = 172

Possibly still a valid answer, though.

 

 

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Answer:

((Bottom Right/Bottom Left)+Top Right)*Top Left, i.e. for 4th diagram ...

(6/2 + 3)*5 = 30

Edited by rocdocmac
No abbreviations

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