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form: 36^k - 5^m


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I am missing how that proves k=1 and m=2 is the smallest

 

Powers of 36 have last digit of 6; powers of 5 have last digit of 5.

Their (positive) differences have a last digit of 1, so numbers other than 1 11 21 31 41 51 ... are excluded.

k=1 and m=2 gives 11 - at worst the second smallest result.

Since k-man showed that 1 must be exclude, 11 is smallest result.

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