BMAD Posted October 31, 2014 Report Share Posted October 31, 2014 Place the remaining numbers from 4 to 10 in the seven divisions of the above figure so that the outer divisions total 30 and each geometric figure totals 30. 1 Quote Link to comment Share on other sites More sharing options...
0 Perhaps check it again Posted October 31, 2014 Report Share Posted October 31, 2014 BMAD, please clarify what "outer divisions" mean. For instance, it look likes the division that has 2 in it and the three divisions that share parts of the perimeter of the division that has 2 in it are inner divisions. Then, it looks like the outer divisions are the three divisions that have 1 and 3 inside of them, respectively, and the division with the far right portion of the circle. Quote Link to comment Share on other sites More sharing options...
0 Perhaps check it again Posted October 31, 2014 Report Share Posted October 31, 2014 BMAD, which of the seven divisions are you calling "outer divisions?" Can you label them in a diagram? Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted October 31, 2014 Report Share Posted October 31, 2014 BMAD, I like the puzzle. Thanks.The outer divisions can't be disjoint. Their numbers would sum to 90 > 55. So, yeah, what are they? Or, does "total 30" mean that could individually be say 8, 10 and 12? If so they could be the disjoint portions of the figures.Labels would help. Quote Link to comment Share on other sites More sharing options...
0 DejMar Posted October 31, 2014 Report Share Posted October 31, 2014 (edited) The outer regions are areas where the geometric figure is not intersected by another. Let the sequence of numbers relate to the following, such that the r is rectangle, c is circle, t is triangle; with single letters denote the division where the geometric figure is not intersected by another geometric figure, and multiple letters denote the divisions where the geometric figures intersect: r, rc, rct, rt, c, ct, t solution: 10, 5, 8, 4, 9, 6, 7 Edited October 31, 2014 by DejMar Quote Link to comment Share on other sites More sharing options...
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BMAD
Place the remaining numbers from 4 to 10 in the seven divisions of the above figure so that the outer divisions total 30 and each geometric figure totals 30.
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