Perhaps check it again
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Perhaps check it again added an answer to a question Center of Gravity
No, I would have no reason to consider the [placement of the] heads, because it is a matchsticks puzzle.
The matchsticks puzzles have never limited themselves to placement of the heads. If you had wanted
that extra condition, then you are changing what kind of traditional puzzle this is and not announcing in
the rules.

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Perhaps check it again added an answer to a question Center of Gravity
Incorrect, TimeSpaceLightForce.
In my explanation and diagram, I already showed that

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Perhaps check it again added an answer to a question Center of Gravity
Here is a diagram of the solution:

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Perhaps check it again added an answer to a question Center of Gravity
** This is my actual answer for the puzzle:

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Perhaps check it again added an answer to a question Horizontally randomly moving particle
The ways that 6 moves that begin and end at point A can be diagrammed:
where the moves happen to be completely to the left of A
where the moves happen to be completely to the right of A
where the moves start to the left of A but then eventually cross A before ending at A
where the moves start to the right of A but then eventually cross A before ending at A
Does anyone see more ways (paths) for any of the four categories above?
I am not seeing any more than what I listed in the spoilers.

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Perhaps check it again added an answer to a question Horizontally randomly moving particle
gavinksong,
your number of ways for the six moves versus mine is off by two. I won't state
whether it's by lower or higher.
I don't see your method as fitting here. However, maybe it (your use of taking
combinations) can be used as part of a larger different method.
The problem is still open.

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Perhaps check it again added a question in New Logic/Math Puzzles
Horizontally randomly moving particle< g  f  e  d  c  b  A  B  C  D  E  F  G >
A particle originates at point A and can move left one point or move right point for any move.
It cannot be stationary for any move.
For two moves, the ways can be diagrammed like this:
ABC
ABA
Abc
AbA
Two of those ways begin and end with the particle at the starting point A.
Question: For six moves, how many of the ways begin and end with the
particle at the starting point A?
 5 replies
 4381 views

Perhaps check it again added an answer to a question Orange square
1 for being an actual nonapology
2 for deflecting onto me
3 for continuing to be an actual nonapology
4 for continuing to deflect onto me
                                        

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Perhaps check it again added an answer to a question Orange square

Perhaps check it again added an answer to a question n!+1 is composite
"Composite" refers to the number having at least two distinct positive integer divisors.

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Perhaps check it again added an answer to a question Orange square
"I'm getting quite a collection of bonanova stars. (emoticon with big grin)
Well, if you don't toot your own horn, others probably won't come along and do it for you.
Someone should send you some ointment to put on your back where you have been frequently patting it.

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Perhaps check it again added an answer to a question Polygons make a line
I stated "No line can pass through all the interiors of the the three triangles."
BMD, you stated "Why cant [sic] a line pass through [triangle] ABE and the common point of
[triangles] ACD and EDF?"
In my attempt to work on the problem, I misunderstood "crossing a polygon" from the
original post and changed the subject.
But, with you asking me that question (in the quotes just above), you changed the subject.
I never addressed/denied that situation. It's not a line passing through the interiors
of three triangles anyway.

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Perhaps check it again added an answer to a question Segments on a line
I didn't question that "do not intersect each other" means that they do not overlap,
meaning that the [line] segments do not have any points in common.
But I can always have a situation where condition 2 occurs. That is why I claim
there are other words/conditions/restrictions/qualifiers left out.

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Perhaps check it again added an answer to a question Polygons make a line
I claim it's not true, and I show it with a counterexample.
In the xyplane, let the following points be labelled as such:
A = (0, 1)
B = (1, 1)
C = (1, 0)
D = (0, 0)
E = (1, 0)
F = (0, 1)
Triangle ABE shares point A with triangle ACD.
Triangle ACD shares point D with triangle EDF.
Triangle ABE shares point E with triangle EDF.
No line can pass through all the interiors of the three triangles.

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Perhaps check it again added an answer to a question Segments on a line
BMAD, it looks like your problem statement is incomplete.
I read it as "Given 50 [line] segments on the [a] line."
It seems you left out a key word or words, because these line segments could be intersecting each other,
or not intersecting each depending on where they are.

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