[wolfgang]

Out of these combinations,find out number 34...have a good time....

1d,4b,4c,1a,3a,2c,2b,3d,2a,3c,3b,2d,4d,1b,1c,4a

[Guest]

I just had this idea... I don't know if this is the answer you are looking for...

If we assume the base 24, 0-9 numbers and letters a onwards from 10-23 then 1a = 34

Similarly, in base 23, 1b=34

In base 22, 1c=34

In base 21, 1d=34

[wolfgang]

I just had this idea... I don't know if this is the answer you are looking for...

If we assume the base 24, 0-9 numbers and letters a onwards from 10-23 then 1a = 34

Similarly, in base 23, 1b=34

In base 22, 1c=34

In base 21, 1d=34

nope...sorry....try something else...ty

[Guest]

How about

3d? 3 is the tens digit, and d = 4 if you go by 1 = a, 2 = b, and so on. thus, 3d = 34

[Guest]

34 is in place or equal to 3d..............

[mewminator]

are the combinations arranged, or are they random, or am I to figure that out?

let the number be x and the letter y

x could be tens and y units (in that case the answer is 3d) or vice versa (4c)

x could be the number of my current cycle around the alphabet and y could be an addition to it (26 (x - 1) + y) but that won't work unless I tweak it like this (26 (x - 1) + xy) then the answer would be 2d

one of a, b, c, or d = 17 or 34 and the answer is 2a, 2b, 2c, 2d, 1a, 1b, 1c, or 1d unless I decide to include fractions then it would just be a mess (11.333 or 8.5)

x could be how many times y (as a letter) has been included in the word thirty-four... the only problem is that 34 doesn't contain a's, b's, c's, or d's

multiplying x by y (as a number) then adding it to the next number until I reach 34:

1d + 4b + 4c +1a +3a +2c

=1 x 4 + 4 x 2 + 4 x 3 + 1 x 1 + 3 x 1 + 2 x 3

=4 + 8 + 12 + 1 + 3 + 6

= 34

therefore the answer is 2c

I wonder if any of this is correct... or am I at least on the right track

Edited December 9, 2011 by mewminator

[Guest]

3d

[CaptainEd]

If you plot these as locations in a 4x4 grid, with rows labelled 1-4 and columns labelled a-d, the sequence Wolfgang has produced is symmetric about the center of the grid.

That is, if you view the two characters as RC (row, column), and number the sequence items from 0 to 15,

C(i) = 4-C(15-i),

R(i) = 4-R(15-i)

I think it's interesting that his sequence completely fills the 4x4 grid and extends no farther.

I think it's interesting that his sequence exhibits this symmetry.

I have NO CLUE how this relates to the location of 34.

Sorry...

[wolfgang]

are the combinations arranged, or are they random, or am I to figure that out?

let the number be x and the letter y

x could be tens and y units (in that case the answer is 3d) or vice versa (4c)

x could be the number of my current cycle around the alphabet and y could be an addition to it (26 (x - 1) + y) but that won't work unless I tweak it like this (26 (x - 1) + xy) then the answer would be 2d

one of a, b, c, or d = 17 or 34 and the answer is 2a, 2b, 2c, 2d, 1a, 1b, 1c, or 1d unless I decide to include fractions then it would just be a mess (11.333 or 8.5)

x could be how many times y (as a letter) has been included in the word thirty-four... the only problem is that 34 doesn't contain a's, b's, c's, or d's

multiplying x by y (as a number) then adding it to the next number until I reach 34:

1d + 4b + 4c +1a +3a +2c

=1 x 4 + 4 x 2 + 4 x 3 + 1 x 1 + 3 x 1 + 2 x 3

=4 + 8 + 12 + 1 + 3 + 6

= 34

therefore the answer is 2c

I wonder if any of this is correct... or am I at least on the right track

These combinations are arrenged in such a manner so that any change in the sequence will not give the same results. Edited December 10, 2011 by wolfgang

[wolfgang]

If you plot these as locations in a 4x4 grid, with rows labelled 1-4 and columns labelled a-d, the sequence Wolfgang has produced is symmetric about the center of the grid.

That is, if you view the two characters as RC (row, column), and number the sequence items from 0 to 15,

C(i) = 4-C(15-i),

R(i) = 4-R(15-i)

I think it's interesting that his sequence completely fills the 4x4 grid and extends no farther.

I think it's interesting that his sequence exhibits this symmetry.

I have NO CLUE how this relates to the location of 34.

Sorry...

Woooow you are very close....!!

[CaptainEd]

I sure don't FEEL close!

By the way, there's a LOT more symmetry--the sequence appears to be a Hamiltonian circuit around a 2x2x2x2 hypercube. But I'm still missing a couple of fundamentals.

1) Perhaps we are to add one or two dimensions (egad, maybe 4 more dimensions!)

2) But his sequence always moves to a new dimension before finishing the old ones. However, this sequence has now completely filled the 2x2x2x2 without starting into new ones.

3) and I have no idea how 1-4 relate to a-d. If we see them as hexadecimal numbers, the gap between 4 and A is not a convenient one, I could be more comfortable (still clueless, but more comfortable) if a-d had been c-f.

This is very interesting wolfgang, thanks for the workout...still working...

[wolfgang]

I sure don't FEEL close!

By the way, there's a LOT more symmetry--the sequence appears to be a Hamiltonian circuit around a 2x2x2x2 hypercube. But I'm still missing a couple of fundamentals.

1) Perhaps we are to add one or two dimensions (egad, maybe 4 more dimensions!)

2) But his sequence always moves to a new dimension before finishing the old ones. However, this sequence has now completely filled the 2x2x2x2 without starting into new ones.

3) and I have no idea how 1-4 relate to a-d. If we see them as hexadecimal numbers, the gap between 4 and A is not a convenient one, I could be more comfortable (still clueless, but more comfortable) if a-d had been c-f.

This is very interesting wolfgang, thanks for the workout...still working...

Thank you Dear...I am so glad to hear this....sometimes,the situation is not so complex as we immagine!...take it easier....!!!

[Guest]

Sum all the series from 1a to 4d, and divide them to 8, there is your 34

[wolfgang]

Sum all the series from 1a to 4d, and divide them to 8, there is your 34

?? ..what??

[wolfgang]

we can obtain ten times 34 out of this sequence .

[curr3nt]

Sum all the series from 1a to 4d, and divide them to 8, there is your 34

He thinks you gave the instructions to a magic square.

1d,4b,4c,1a,3a,2c,2b,3d,2a,3c,3b,2d,4d,1b,1c,4a

  4 14 15  1

  9  7  6 12

  5 11 10  8

 16  2  3 13

Which your new hint supports.

Edited December 12, 2011 by curr3nt

[Guest]

He thinks you gave the instructions to a magic square.

1d,4b,4c,1a,3a,2c,2b,3d,2a,3c,3b,2d,4d,1b,1c,4a

  4 14 15  1

  9  7  6 12

  5 11 10  8

16  2  3 13

Which your new hint supports.

so, the 34 we've been looking for is everywhere...in every horizontal, vertical and main diagonal line.

[CaptainEd]

Yes, that solution is shockingly direct, curr3nt! Good job! What a relief!

[mewminator]

I see a whole lot of 34's

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

I think that's enough

Edited December 13, 2011 by mewminator

[wolfgang]

He thinks you gave the instructions to a magic square.

1d,4b,4c,1a,3a,2c,2b,3d,2a,3c,3b,2d,4d,1b,1c,4a

  4 14 15  1

  9  7  6 12

  5 11 10  8

16  2  3 13

Which your new hint supports.

Yes...I gave the instructions to a magic square,by giving the squares on X-axes,letters(a,b,c,and d)

and giving numbers(1 to 4) to Y-axes squares.

now,1d will mean the square for 1,

and 4b will indicate where number 2 should be,,,and so on

[robo]

Using the grid mentioned by CaptainEd, I entered numbers 1-16 in the grid.

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

And I find that each row, column and diagonal sum up to 34

[wolfgang]

Using the grid mentioned by CaptainEd, I entered numbers 1-16 in the grid.

4 14 15 1

9 7 6 12

5 11 10 8

16 2 3 13

And I find that each row, column and diagonal sum up to 34

Thats right...and you can enter numbers in the grid according to my combination also.