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MISTRESS

If it's 0, then 2nd is Y because of mYstical with one of first four correct and out of those Y to I only change.

Reason mystical's correct must be from myst: inimICAL has 0 with last four common.

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If REINLESS=1 then ?I??????

MISTRESS=3 and M_ST____=1 or 0 from MYSTICAL=1

____R__S is eliminated from repoRted=0 and rainbowS=0

This leaves M_ST____=1 and _I___ES_=2 or 3

If REINLESS=1 then _____ES_=1 and so _I______=1 since _I___ES_=2 or 3

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JDave - were you actually proposing any letters as solved/proven?

Thalia - I didn't score 'molocule' as there is no such word that I'm aware of - I didn't think that molecule would achieve the same elimination that you appeared to want so I didn't replace it.

????????

RAINBOWS - 0 	INIMICAL - 0 

REPORTED - 0 	MISTRESS - 3 

PRECLUDE - 0 	DISTRUST - 3 

COLORFUL - 0 	REINLESS - 1 

MYSTICAL - 1 	FURTHEST - 3 


Score Changes: none yet

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????????

RAINBOWS - 0 	INIMICAL - 0 	MOLECULE - 0 

REPORTED - 0 	MISTRESS - 3 

PRECLUDE - 0 	DISTRUST - 3 

COLORFUL - 0 	REINLESS - 1 

MYSTICAL - 1 	FURTHEST - 3 


Score Changes: none yet

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JDave - were you actually proposing any letters as solved/proven?

Yeah, REINLESS=1 means ?I?????? is proven unless my logic was bad. I should have said If REINLESS=1 then ?I?????? is proven.
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JDave - wasn't sure whether you were proposing others too or not.

?I??????

RAINBOWS - 0 	INIMICAL - 0 	MOLECULE - 0 

REPORTED - 0 	MISTRESS - 3 	FIFTYISH - 2 

PRECLUDE - 0 	DISTRUST - 3 	MISTRUST - 3 

COLORFUL - 0 	REINLESS - 1 	CORTICAL - 1 

MYSTICAL - 1 	FURTHEST - 3 


Score Changes: JDave +5

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???T???? is proven.

M_ST____=1 because MYSTICAL=1 and inimICAL=0 and the I in 2nd position is proven.

MISTRUST=DISTRUST=3 means that the M is not scoring, so __ST____=1

CORTICAL=1 means that __RT____=1 since CO__ICAL is eliminated by COlorful=0 & inimICAL=0

If __R_____=1 then the S in __ST____=1 cannot score and ___T____=1

This is contradictory because it would result in __RT____=2

Since __R_____ cannot score, then __RT_____=1 requires ___T____=1

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Just to add another proof to that long one...

?????E?? is also proven.

REINLESS=1 leads to _____ES_=1 since the letters REINL__S are eliminated by REported=raINbowS=precLude=0

FIFTYISH=2 eliminates the S because the two points come from _I_T____=2 which is already proven.

With the S eliminated, _____ES_=1 becomes _____E__=1.

And another. Why not.

???????T is proven

MISTRESS=3 results in M_S_R_SS=0 since ?I?T?E?? is proven.

MISTRUST=3 reduces to _I_T_U_T=3. The _I_T____=2 is proven leaving _____U_T=1

The U is eliminated by preclUde=0, so _______T=1.

?I?T?E?T

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