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dark_magician_92

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Posts posted by dark_magician_92

  1. Thank you to all of you i.e.Common Zenz , Current, thoughtfulfellow, tonyd and spamwolf. All your answers are right. And now the funny thing, after checking your answers and method (which was quite different from mine), i decided to post my solution and it was while typing when i realized That I MADE ONE OF THE MOST SILLIEST MISTAKES bcoz of which the answer which shud have been = 37/72 = 111/216 , turned out to be 135/216. Similar sort of error was in the 2nd part. However i am glad that you all participated. Will post some problems, if i come across some and hopefully not mess up the answers :D :D

  2. My friend Found this somewhere and i calculated a different answer than what he told was. Plz mention ur approach and answer of this problem!!

    Rules of Game:-

    "We each get one die, the highest die wins. If we tie, I win, but since you always lose when you roll a one, if you roll a one you can roll again. If you get a one the second time you have to keep it."

    What is each person's probability of winning?

    What are the probabilities of winning if you can keep rolling until you get something besides a one?

  3. eva and amanda are against, id amanda is truthful then melinda is girlfriend, and venessa is sister and eva is truthful but both amanda and eva cant be truthful. hence amanda is a liar and melinda is not the girlfriend and hence eva is tuthful but venessa tries to tell her a liar, hence venessa is also a liar and makes melinda truthful. hence venessa is not the sister, as per melinda and hence amanda is the sister

  4. cant think of a solution yet but

    if the emperor is allowed to mix, then how we divide should not matter.however if its like that the emperor plans to kill us by minimising our

    probaility then he wud mix in a way that in 1 bowl it will have may be 1 black and other will have 50W+49B. so we can check the bowl with more ,marbels and select 1 with P=50/99=50.50505050.... %

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