Nine years ago,when Mike was 6 years old, he stood against a tree and drew a black line on the tree trunk with a permenant marker ( suppose the line will stay forever!)indicating his height at that time.

Yesterday, he stood again at the same place as he did before and drew a red line on the tree trunk.

1- let the growth rate of Mike to be constant,( 2.55 inches )/ year.

2- let the growth rate of the tree to be constant also ( 18.21 inches )/ year.

Which line will be above the other?the black or the red?why?

How many inches will be the distance between the two lines?

black will be above by (18.21-2.55)*9 inches if both r increasing at constant rate and the tree increases from roots/base

There are three people, they are (and will) be born on the same date 12 years and one month apart from eachother. The first of these people will be born later this year. The second persons birth year, when the individual digits are summed eaquals the day of their birth. The average of the third and first persons month of birth of birth squared eaquals the day of their birth. The older the person the later the month. What are the three birthdays?

excuse me but, it shud be "equal to the date of their birth" not "day of their month" and also how is it possible that "the older the person the later the month"??

Our grocer got a new shipment of oranges.

Tired of he held a quick clearance sale for his triangle

oranges, and arranged his new stock into a square pyramid. That is, the

topmost orange sat on a layer of four [2x2], which rested on a layer of nine

[3x3] and so on until the final orange was found to exactly complete the

bottom-most square layer of dimensions [nxn]. Of course, he built his square

pyramid from the bottom up. Describing from top down just seemed more

convenient.

But then came the inevitable encounter with the cell phone shopper's cart!

Amazingly, thought the grocer, and it was in fact amazing, as you'll discover,

the fallen oranges became a new square array, with every orange touching

the floor.

Just one question remains. What was n?.

i have concluded that we need to solve the equation n(n+1)(2n+1)/6=t^2, where t is a natural no.

however i am unable to slove further, some hints of approaching the problem plz.

[Funny Classroom]

Student: hey,teacher is commng

Teacher: Good morning,class

All Student is quiet.

Teacher: Why are you don saying good morning?

All Student is sleep.

Teacher: argh, They sleep in classroom!!

Teacher: wake up everyone!

All Student is run out and go home safely.

Teacher: I hate this student! not go out and go home!

--------------------------------------------------------

Student 1 is smoking.

Student 2: why are you smoking in this school.

Student 1: because teacher told me smoking.

Student 2: huh? what are you talking about? teacher is behind you

Teacher: Hey why are you smoke!

Student 1: because he told me smoking.

Student 2: not me. you lie.

hey sorry to say but i didnt get the jokes, you probably used some translating software, anyways all the best

Test ur IQ

If

9 + 3 = 722

5 + 7 = 536

8 + 6 = 845

4 + 4 = 613

Then

7 + 2 = ?

This is a Real test.

7+2=(REVERSE of 7*2 and (2-1))=411

a old guy had 17 cows and 3 sons.one day father died and according to his will he said his eldest son was very much helpful so give him half of all animals and no 2 son also helped me a lot so give him third part of all animals and youngest son was very careless and not helping anyway so give him ninth part og all animals.now question is how to divide cows between 3 sons without killing any cow and according to their father s will.

9cows,6cows and 2 cows resp.

During WWII there was a bridge connecting Germany and Switzerland and on the German side there was a sentry tower with a guard in it. He would come out every three minutes to check on the bridge and he had orders to turn back anyone who tried to get into Germany and shoot anyone trying to escape without a pass. There was a woman who desperately needed to get into Switzerland and she knew she didn't have time to get a pass. It would take her at least six minutes to cross the bridge but she managed to do it. How?

she can just chamge her face towards the germany side as soon as 3 mins pass and the gaurd comes, so that the guard send her to swiss territory

What object has keys that open no locks, space but no room and you can enter but not go in?

keyboard

My friend is an athlete,he is a marathon runner (but he had never won),he says always:

well,if they let me start running 14 Minutes before the others, I`ll win the race even if the best runner in the world( who needs 2 hours ,3 minutes and 59 seconds to complete the marathon ),was in the race.

At which speed (Km/h)(as an average) can my friend run? if he can win( under this condition) the world champion in one second.

Note:The marathon is defined as 42.195 km

18.35 km/h

[The Green Glass Doors]

Green glass doors...i make up a rule, and you ask words to see what gets though the "green glass doors". when you think you know the rule, put it in a spoiler. words dont have to be in a spoiler...

ready? go!!!

green

glass

doors

apple carrot yummy

the pit turned sideways

then the ying yang 3

pit upright

and the snake is free

yes i got it! it is ..... ah...umm...um..wait i forgot

I'm thinking of a polynomial P(x) which

has non-negative integer coefficients.

Now, P(1)=14 and P(15)=5296846548.

What is the polynomial, P(x), of which

I think?

Please use spoilers.

f(x)= 2(x^8)+(x^7)+4(x^4)+x^3+3x+3

the car at 8am is the 240th car, isnt it?

so car at 9am is 300th hence last no. shud be 8 only (it is the 60th 5th car). so answer shud be 70694

No...please see Maurice answer...thanks

One way to show the e^(1/e) limit is this...

so we have y' = (y^2) / (x - x y ln x)

we'll have critical points where y' is 0 or undefined.

0 when y^2 = 0, so y = 0. We find the inverse function x = y^(1/y) and y=0, so 0^(1/0) isn't really defined. So look just at the bottom:

x(1 - ylnx) = 0

x = 0 and 1 = ylnx

1 = ylnx

raise e to both sides to get:

e = y

then use the inverse (x = y^(1/y)) to get x = e^(1/e)

That's one way to do it, kind of sloppy though

thanks a lot, i solved the problem upto that "ylnx=1", but couldnt solve further. Thanks n I feel happy now to have joined brainden

half a dime

You have a dime and a dollar...

you buy a dog and a collar...

if the dog costs as much as the collar plus a dollar...

how much is the collar?

Prove me wrong...

-20=-20...

16-36=25-45...

4^2-9*4=5^2-9*5...

4^2-9*4+81/4=5^2-9*5+81/4...

(ok this next parts tricky but it works out)...

(4-9/2)^2=(5-9/2)^2...

4-9/2=5-9/2...

4=5...

hehe everything is right except the last step shud have been

(4-9/2)=+(5-9/2) or 4-9/2=-(5-9/2)

I'm thinking of a polynomial P(x) which

has non-negative integer coefficients.

Now, P(1)=14 and P(15)=5296846548.

What is the polynomial, P(x), of which

I think?

Please use spoilers.

some hints plz.

Conrad has no job ,He spend the whole day watching cars passing the street in front of his apartment.His hobby is to write down there Numbers !and try to find something common between them.These are his conclusions :-

1- the cars pass through at (1min.)interval,one car at a time.

2- each car has a (five digits)number.

3- each second car(i.e the car No. 2,4,6...etc.) has a middle number(3rd.No.)ranging between(4 and 6),i.e.the car No. 2 has No.4 in the middle,the car No. 4 has No. 5 in the middle,the car No. 6 has No.6 in the middle...and again 4,5,6. for the cars 8,10,12

and so on.

4-each 3rd.car has a(4th number) either(0,1 or 2) as described before.

5-each 4th car has a(1st number) either(2,3 or 4),as above.

6- each 5th car has a (last number)either(6,7 or 8).

7-each 6th car has a(2nd number)either(8,9 or 0).

He wrote a car number(71684)at 8.00 am.,then he went to have his breakfast.

exactly ,at 9.00 O`clock am. (after one hour),a car chased by the police went along this sreet.Conrad was able to estimate its number !

Can you?

80694 or 49608

[Alex gets even with writersblock. Or does he?]

ur r right however the answer would be i gues 99.99999 something, so nearest point of % is 100 only

Not sure if this is relevant but just say, for example, 10% of infinity, ?/10, is still ? but a differnet level of infinity correct?

like

(?/10) / ?

it wouldnt be ?/? as in 1 as in 100%.... it would be .1 as in 10%

Am I just shootin in the dark here or do I have a slembance of a point? Help me out here lol

cot

"nothing"

Riddle 7) This word has 7 letters

If you eat it, you'll die

If you drink it, you'll die

Poor people don't need it

Rich people do need it

What is the word????

David

Riddle 3) David's Father: David's father has 3 kids... Snap,Crackle, and _____.

fire?

Riddle 1) One day, Fred got hungry... He went in the kitchen, there was a loud noise, and Fred was dead. Any solutions to the reason why?

Riddle 2) This one may have been used before...

Young, I am tall

Old, I am short

My life brings you light

Your breath is my foe

????? Please place answers in SPOILERS!!! There will be more riddles added on later. Contributions welcome!!!

Divide the keys in 3 sets:-

set 1 having key 1,2,3 and 4

set 2 having key 5,6,7 and 8

set 3 having key 9

Case 1:- let the correct keys be 1,2 and 3

Q1. is there any set with all the 3 keys?

A1.Yes

Q2. Is the 1st set having the 3 keys?

A2. Yes

Q3.Are keys 1,2and 4 all correct ones?

A3. No

Q4.Are keys 1,3 and 4 correct?

A4.No

Q5. Are keys 2,3 and 4 correct?

A5.No

so we know 1,2 and 3 are correct

Case 2:- 4,1 and 9

Q1.any set with 3 keys?

A1. No

Q2.is 3rd set one of the right key?

A2.Yes

Q3.Is 1st set having 2 keys correct?

A3.Yes

Q4.Is 1,2 and 3 having both correct keys?

A4.No (that means 4 is correct one)

Q.5 Is 2,3 and having a correct one?

A5.Yes

Q.6 is 2 correct?

we got the keys

Next case:- 1,2 and 5

Q1.any set with 3 keys?

A1. No

Q2.is 3rd set one of the right key?

A2.no

Q3.Is 1st set having 2 keys correct?

A3.Yes

Q4.Is 1,2 and 3 having two correct keys?

A4.Yes (that means 4 is not correct one)

Q.5 Is 1,2 correct?

Q6.Is is 2,3 correct

similarly 2 more questions for 5,6,7and 8

so i guess 8 questions in worst possible case.

A prisoner must cross three locked gates inorder to escape the jail.With him there is a man having 9 keys,these keys have numbers,1 to 9.Only three keys are the right ones(if a wrong key is used to any gate,it will stuck).

The man with keys always tells the truth,and he knows which key fit to each gate.

What is the best strategy to escape through all three gates,if he is allowed to ask only(yes or no)questions.

The minimum question number is better.

[Alex gets even with writersblock. Or does he?]

After being done out of a pint of O'Doule's by writersblock

last night at Morty's, Alex conjured up a question calculated

to get him even.

After WB had downed his cool one, Alex proposed a double or

nothing puzzle. To the nearest percentage point, he asked,

what percentage of all numbers contain at least one 3?

For example, 13, 31, 33 and 103 all contain the digit 3 at least once.

But 1, 2, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 15, 16, 17, 18, ... well

you get the idea ... don't contain the digit 3 even once.

Now I know there's a lot of numbers to check, so I'll make it

easy for ya, Alex said. I'll give you five multiple choices.

That gives you a 20% chance even if you guess, and much

better odds if you yer' the genius ya' make yerself out to be.

The percent of all numbers containing at least a single "3" is:

[1] 10%

[2] 13%

[3] 33%

[4] 67%

[5] 100%

What was writersblock's choice, and did he win another pint?

it has to be 100% (almost), since we have infinite numbers and we hence have infinite nos. beginning with 3 which increases the %s one after another, till 300 % is about 0.19, due to 300-400, % becomes 0.39 and then 3000-3999, makes it as high as 46% ans so on........