I can find more....but this was the first I tried that fit my equation.
here's a few more. The ones that can have 20 balls added will be marked with asterixes
{1*,1*,9,4}
{4*,12,1,1}
{2*,2*,2*,2*,2*,5,15}
The probability we are trying to keep identical is the probability you draw (with replacement) the same color twice. This is essentially the sum of the squares of the probability to draw a given color.
Yes, the probability to draw one of the 2s is 10%....but the probability you draw it twice is 1%....just as PolishNorbi calculated.
Similarly with 60% = .6, .6^2 = .36 = 36%.
If {2,2,2,2,12} isn't an answer to your puzzle, then it looks like you didn't explain your question well....but as explained...it was an interesting exercise.
Just as a matter of clarification.....please fully parenthesize the equation (at least with regard to division)...
2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+36698/(4895-5884*102504)=(square root of x)*698/(56x*589x*42x+69/(square root of -90)) ?
or
2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+(36698/4895)-5884*102504=(square root of x)*(698/56x)*589x*42x+69/(square root of -90) ?
And as a response to DemonWolf44,
"Not possible for two reasons I see."
1. Your doing squareroots of negatives which are imaginary numbers.
yes...the answer may or may not be a complex number.....that doesn't mean it isn't possible.
2. You can't have radicals in the denominator of a fraction.
Sure you can, and you can move them if needed. (eg, 1/sqrt(2) = sqrt(2)/(sqrt(2)*sqrt(2)) = sqrt(2)/2 )
Definitely driving at an unsafe speed....so the officer should give you a ticket for speeding.
And if the fine grows linearly (or more) with speed....I'd say you should have gotten the ticket for running a red light instead!