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plainglazed

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Posts posted by plainglazed

  1. WEANS

    if WEANS =  1 then W is first

    not E or N from BEING = 0, not A fron AGAIN = 0, not S from BEANS = 0

    if WEANS = 0 then R is middle

    only letter different than WERNS - 1

  2. I'll need help with the scoring.  Especially since this is somewhat uncanny.  Probably deserves extra credit but the OP would have to jump in yet he would be the recipient...

    R E P L Y

    dang! no joke.

     

  3. Spoiler for some supporting math

     

    I have the same calculations as DejMar but with an assumption that I cannot yet prove yields a minimum web length.  In my last response I thought this problem must have some grand symmetry and assumed the red lines in my drawing (above) must be the same distance x from their nearest two sides of the cube described by the eight corks. The following assumes a magical 30 degree angle of those red lines:

    TSLF3D3.png


    f(x) = 8/sqrt(3) + 4(1-2x)/sqrt(3) + 1-2sqrt(1/12-x2)-(1-2x)/sqrt(3)
    f(x) = 8/sqrt(3) + 3(1-2x)/sqrt(3) + 1-2sqrt(1/12-x2)
    f(x) = 8/sqrt(3) + sqrt(3)(1-2x) + 1-2sqrt(1/12-x2)
    f'(x) = -2sqrt(3) + 2x/sqrt(1/12-x2)
    f'(x) = 0 when x = .25

    f(x=.25) = 1+9/sqrt(3) ≈ 6.196 

     

  4.  

     

    adding Bb3k's headless stick figure and crunching some numbers:

    TSLFcorks2.png

    8(2x2+.52).5+ 4(1-2x)/3.5+ 1-2x-(1-2x)/3.5

    f(x) = 8(2x2+1/4).5 + 3(1-2x)/3.5 + 1–2x

    f’(x) = 16x/(2x2+1/4).5 – 2(3.5) – 2

    f’(x) = 0 when x = ~.195

    f(x=.195) = 4.568 + 1.409 + .258 = 6.235

     

    the sqrt(3) comes from TSLF's 2D connect the dots:

    TSLFroads2.png

    f(x) = 4(x2+.52).5 + 1 – 2x

    f”(x) = 4x/(x2+1/4).5 – 2

    f’(x) = 0 when x = 1/2(3.5) = ~.289

    tan-1(1/2(3.5)/.5) or tan-1(1/3.5) = 30°

     

     

     

     

  5. and a Spoiler for some additional thoughts:

     

    I think 1/sqrt3 is more likely than e.  Bb3k's described improvement to tojo982's offering: "The left and right side of the X's are pushed inward to make a 0.5 mile road in the middle."  If we vary the .5 mile connection, we can generalize the length of this path: 

    4sqrt(.52 + (.5tan(a))2) + 1-tan(a)

    where (a) is the angle formed by the y-axis and the X in Bb3k's drawing above.  This expression minimizes when (a) is 30 degrees.

    EDIT:  although now I'm not so sure.  don't know if the rounding in Excel or my calculator is more accurate and the kind of calculus needed here i've long since forgotten.  really quite amazing that the two are so close. in any event, Bb3k's answer I thought was quite clever and satisfied the OP. 

     

    • Upvote 1
  6. Hey hey you two - Wilson, know it's been a while since you posted the above but gotta say, very clever as always - indeed too clever for me.  And just reviewed these and only now do I fully get your previous stab at this one.  Always been fifty fifty on the spelling of that arid wasteland or after meal treat.  Love it.

    T - thanks for the bump.  All's true in your spoiler above with the exception that the spouse is not gender specific.

    Cheers

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