You have 6 basket balls - 3 brown, 2 red, and 1 green. What is the probobility of blindly putting them in semetrical order....

you cant - 0% or 0/100

if you have an odd # of basket balls, then one HAS to go in the middle - if there is also another odd #, then you need two different spots for middle - nope! sorry!

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## peace*out

You have 6 basket balls - 3 brown, 2 red, and 1 green. What is the probobility of blindly putting them in semetrical order....

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