I might be a writer

[bonanova]

FF?

[Wilson]

Best I've got......

Spoiler

2^8 kinda hints at 2^B  .....so is it ....2B or not 2B?  William Shakespeare?

 

[Wilson]

Spoiler

Norma Stits?

 

[bonanova]

26 minutes ago, Wilson said:

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Norma Stits?

Not who I had in mind, although I can see where you're headed on this.

 

[Wilson]

9 hours ago, bonanova said:

 

Yeah, I knew it wasn't gonna be her.

I do know however that you are a genius with numbers  and that the answer will probably come from that realm....?

Spoiler

FF(hex), 255(dec), 11111111(binary)

Still trying to parse this into an answer. On the right track?

[bonanova]

Yes, sir, that is exactly the right track.

[Shakeepuddn]

Is it some sort of . . .

Spoiler

Verilog code?

 

[bonanova]

15 hours ago, Wilson said:

Best I've got......

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2^8 kinda hints at 2^B  .....so is it ....2B or not 2B?  William Shakespeare?

 

That's the answer I'm looking for. If you put your two posts together, you've got it.

Spoiler

FF?

1. What does FF? mean?
   It clearly means "FF" is the question.
    
2. Seriously. What does "FF" mean?
   It's a hexadecimal number.
   Hex numbers have digits { 0 1 2 3 4 5 6 7 8 9 A B C D E F } with values 0-15 and
   binary representations { 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111 }.
   That said, FF can be expressed as 1111 1111.
    
3. I'm waiting for something useful
   OK. Now we have to do some reverse engineering.
   Recall that 2 (hex) is 0010 and B (hex) is 1011?
    
4. *Tapping fingers*
   Almost done.
   In binary logic, "not" changes 1 (true) to 0 (false) and vice versa.
   And "A or B" is true if either of A or B is true.
    
5. Seriously dude. This was a word riddle?
   OK I could have posted it in the logic puzzle thread.
   But you solved it, didn't you?
    
6. If you say so, but I don't see
   2B = 0010 1011.
   Not 2B = 1101 0100.
   (2B) or (not 2B) = 1111 1111 = FF.
   That, as we have just shown, is the question.
   And Willie S. just might be a writer.
   Very nice solve.

 

 

[Wilson]

Thanks bonanova  for indulging my flawed logic, and  for explaining the steps that I was clueless about :-)