rocdocmac Posted December 17, 2017 Report Share Posted December 17, 2017 (edited) Replace the ? in each of these sequences with the correct value ... [1] 1 4 17 54 145 368 945 ? [2] 0 6 21 405 -504 ? [3] 2 15 10001 215441 ? [4] 7 8 5 3 9 8 1 6 3 ? [5] 15 52 99 144 175 180 147 ? [6] 0 5 8 8 2 3 5 2 9 4 ? [7] 1 2r πr² ⁴/₃ πr3 ? [8] 4/10 ?/102 168/103 1229/104 9592/105 78498/106 [9] 3 23 229 2869 43531 ? [10] 14 21 13 2 5 8 0 19 5 18 9 5 ? [11] 6 8 5 8 4 0 7 3 4 6 ? [12] 1 3 8 22 65 209 732 2780 ? Edited December 17, 2017 by rocdocmac No title! Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted December 18, 2017 Report Share Posted December 18, 2017 21 hours ago, rocdocmac said: Replace the ? in each of these sequences with the correct value ... 1 4 17 54 145 368 945 ? 0 6 21 405 -504 ? 2 15 10001 215441 ? 7 8 5 3 9 8 1 6 3 ? 15 52 99 144 175 180 147 ? 0 5 8 8 2 3 5 2 9 4 ? 1 2r πr² ⁴/₃ πr3 1/2 π²r4 { Can be written: r0 2r1 πr2 4/3 πr3 1/2 π²r4 ... } 4/10 ?/102 168/103 1229/104 9592/105 78498/106 3 23 229 2869 43531 ? 14 21 13 2 5 8 0 19 5 18 9 5 ? 6 8 5 8 4 0 7 3 4 6 ? 1 3 8 22 65 209 732 2780 ? Quote Link to comment Share on other sites More sharing options...
0 rocdocmac Posted December 18, 2017 Author Report Share Posted December 18, 2017 Spoiler [7] Yes, a relatively easy one! The volume of a glome (4D sphere). Next one would be ⁸/₁₅ π2r 5 Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted December 18, 2017 Report Share Posted December 18, 2017 12 hours ago, rocdocmac said: Reveal hidden contents [7] Yes, a relatively easy one! The volume of a glome (4D sphere). Next one would be ⁸/₁₅ π2r 5 Spoiler More precisely, volumes enclosed by nD spheres, or of nD balls. Still, I'm wondering about the first term. Does it imply the volume enclosed by a point is 1? Should the first term be 0 r0 ? Quote Link to comment Share on other sites More sharing options...
0 rocdocmac Posted December 19, 2017 Author Report Share Posted December 19, 2017 Spoiler I've been wondering this too! Negative dimension? A one-dimensional ball of radius r is a line segment of length 2r and its zero-dimensional sphere consists of two points separated by a distance of 2r. Therefore, the series probably only starts at 1, i.e. the "volume" of a zero-dimentional ball. Quote Link to comment Share on other sites More sharing options...
0 rocdocmac Posted December 19, 2017 Author Report Share Posted December 19, 2017 Spoiler Let's rather compare this way ... 0D: vol = 1, area = 0 1D: vol = 2r, area = 2 2D: vol = πr² , area = 2πr 3D: vol = ⁴/₃ πr3 , area = 4πr2 etc. Thus, for volume: 1 2r πr² ⁴/₃ πr3 ... but for bounding area: 0 2 2πr 4πr2 ... Quote Link to comment Share on other sites More sharing options...
Question
rocdocmac
Replace the ? in each of these sequences with the correct value ...
[1] 1 4 17 54 145 368 945 ?
[2] 0 6 21 405 -504 ?
[3] 2 15 10001 215441 ?
[4] 7 8 5 3 9 8 1 6 3 ?
[5] 15 52 99 144 175 180 147 ?
[6] 0 5 8 8 2 3 5 2 9 4 ?
[7] 1 2r πr² ⁴/₃ πr3 ?
[8] 4/10 ?/102 168/103 1229/104 9592/105 78498/106
[9] 3 23 229 2869 43531 ?
[10] 14 21 13 2 5 8 0 19 5 18 9 5 ?
[11] 6 8 5 8 4 0 7 3 4 6 ?
[12] 1 3 8 22 65 209 732 2780 ?
Edited by rocdocmacNo title!
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