phaze Posted December 18, 2016 Author Report Share Posted December 18, 2016 E _ _ _ Y FEVER - 0 PITCH - 0 EVERY -2 THORN - 1 EVENT - 1 AVERT - 0 - Araver + 10 EBONY - 3 Quote Link to comment Share on other sites More sharing options...
phaze Posted December 18, 2016 Author Report Share Posted December 18, 2016 E _ _ _ Y FEVER - 0 PITCH - 0 EVERY -2 THORN - 1 EVENT - 1 AVERT - 0 - Araver + 10 EBONY - 3 Quote Link to comment Share on other sites More sharing options...
araver Posted December 19, 2016 Report Share Posted December 19, 2016 --O-- Event=1 and e---y=2 so ---n-=0 Thorn=1 and e---y=2 and avert=0Â so -ho--=1 * Ebony=3Â and e---y=2 and ---n-=0 so -bo--=1 ** From * and ** we get --o--=1. EPOXY Quote Link to comment Share on other sites More sharing options...
phaze Posted December 19, 2016 Author Report Share Posted December 19, 2016 E P O X Y FEVER - 0 PITCH - 0 EVERY -2 THORN - 1 EVENT - 1 AVERT - 0 - Araver + 10 EBONY - 3 EPOXY - 5 - Araver + 20 Â maurice -Â Â 246 plainglazed -Â Â Â 236 phaze -Â Â 223 + 8 = 231 Logophobic - 143 araver -Â 79 + 30 = 109 nana - 10 Quote Link to comment Share on other sites More sharing options...
phaze Posted December 19, 2016 Author Report Share Posted December 19, 2016 E P O X Y FEVER - 0 PITCH - 0 EVERY -2 THORN - 1 EVENT - 1 AVERT - 0 - Araver + 10 EBONY - 3 EPOXY - 5 - Araver + 20 Â maurice -Â Â 246 plainglazed -Â Â Â 236 phaze -Â Â 223 + 8 = 231 Logophobic - 143 araver -Â 79 + 30 = 109 nana - 10 Quote Link to comment Share on other sites More sharing options...
araver Posted December 20, 2016 Report Share Posted December 20, 2016 Cool. I almost forgot the feeling _ _ _ _ _ Quote Link to comment Share on other sites More sharing options...
phaze Posted December 20, 2016 Author Report Share Posted December 20, 2016 emcee beets Quote Link to comment Share on other sites More sharing options...
araver Posted December 21, 2016 Report Share Posted December 21, 2016 8 hours ago, phaze said: Â emcee - 1 beets - 0 Quote Link to comment Share on other sites More sharing options...
phaze Posted December 22, 2016 Author Report Share Posted December 22, 2016 eerie Quote Link to comment Share on other sites More sharing options...
araver Posted December 22, 2016 Report Share Posted December 22, 2016 emcee - 1 beets - 0 eerie - 0 Quote Link to comment Share on other sites More sharing options...
phaze Posted December 22, 2016 Author Report Share Posted December 22, 2016 sober Quote Link to comment Share on other sites More sharing options...
araver Posted December 23, 2016 Report Share Posted December 23, 2016 emcee - 1 beets - 0 eerie - 0 sober - 1 Quote Link to comment Share on other sites More sharing options...
maurice_2.0 Posted December 26, 2016 Report Share Posted December 26, 2016 carat    Quote Link to comment Share on other sites More sharing options...
araver Posted December 26, 2016 Report Share Posted December 26, 2016 _ _ _ _ _ emcee - 1 beets - 0 eerie - 0 sober - 1 carat - 1 Quote Link to comment Share on other sites More sharing options...
maurice_2.0 Posted December 26, 2016 Report Share Posted December 26, 2016 (edited) beret if 2 must be _ _ _ et as beets and eerie = 0, ruling out ber_ _ Â Â Edited December 26, 2016 by maurice_2.0 Quote Link to comment Share on other sites More sharing options...
araver Posted December 26, 2016 Report Share Posted December 26, 2016 _ _ _ E T emcee - 1 beets - 0 eerie - 0 sober - 1 carat - 1 beret - 2, maurice +10 Quote Link to comment Share on other sites More sharing options...
phaze Posted December 27, 2016 Author Report Share Posted December 27, 2016 onset Quote Link to comment Share on other sites More sharing options...
araver Posted December 28, 2016 Report Share Posted December 28, 2016 _ _ _ E T emcee - 1 beets - 0 eerie - 0 sober - 1 carat - 1 beret - 2, maurice +10 onset - 3 Quote Link to comment Share on other sites More sharing options...
phaze Posted December 28, 2016 Author Report Share Posted December 28, 2016 unmet Quote Link to comment Share on other sites More sharing options...
maurice_2.0 Posted December 28, 2016 Report Share Posted December 28, 2016 beset  If 3 then s is 3rd as beets = 0 rules out be and et is known Quote Link to comment Share on other sites More sharing options...
maurice_2.0 Posted December 28, 2016 Report Share Posted December 28, 2016 beset  If 3 then s is 3rd as beets = 0 rules out be and et is known Quote Link to comment Share on other sites More sharing options...
phaze Posted December 28, 2016 Author Report Share Posted December 28, 2016 if unmet = 2 and beset = 2 then try OCTET followed by OWLET if unmet = 3 and beset = 3 then try UPSET if unmet =2 and beset =3 then try ASSET if unmet =3 and beset = 2 then try INLET Â Quote Link to comment Share on other sites More sharing options...
araver Posted December 28, 2016 Report Share Posted December 28, 2016 (edited) * * * E T emcee - 1 beets - 0 eerie - 0 sober - 1 carat - 1 beret - 2, maurice +10 onset - 3 unmet - 2 beset - 3, maurice +5 asset - 5, phaze +15 (who said brute force is dead :P) maurice -Â Â 246 +15 = 261 phaze -Â Â 231 +15 = 246 plainglazed -Â Â Â 236 Logophobic - 143 araver -Â 109 + 9 = 118 nana - 10 Edited December 28, 2016 by araver Quote Link to comment Share on other sites More sharing options...
phaze Posted December 28, 2016 Author Report Share Posted December 28, 2016 maurice -Â Â 246 + 15 = 261 plainglazed -Â Â Â 236 phaze -Â Â 231 + 15 = 246 Logophobic - 143 araver -Â Â 109 + 10 = 119 nana - 10 _ _ _ _ _ Quote Link to comment Share on other sites More sharing options...
araver Posted December 28, 2016 Report Share Posted December 28, 2016 HOSTS Also apparently I can't count to ten. I can't properly explain that so let's just forget you ever saw it. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.