bonanova Posted July 20, 2015 Report Share Posted July 20, 2015 (edited) Using only a straight edge, construct a perpendicular to the drawn diameter of a circle, from a point P outside the circle. Edited July 25, 2015 by bonanova Reinserted image, which had disappeared from my media folder. Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted July 24, 2015 Author Report Share Posted July 24, 2015 Shamelessly bumping this thread. Quote Link to comment Share on other sites More sharing options...
0 Rainman Posted July 24, 2015 Report Share Posted July 24, 2015 What are the allowed operations? Can we only use the standard operations (connect two points or extend a line segment) or may we use other tricks, for example align the straightedge along the diameter and use the other side of the straightedge to draw a parallel line? Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted July 25, 2015 Author Report Share Posted July 25, 2015 Standard. But I think the cat is out of the bag. Still getting used to the new posting protocol. Quote Link to comment Share on other sites More sharing options...
0 Franco Posted July 25, 2015 Report Share Posted July 25, 2015 If I got it right, we just need to construct a short line. Perpendicularity is out of the material contact. Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted July 27, 2015 Author Report Share Posted July 27, 2015 To be more specific, you can draw a line segment between two existing points or extend an existing line segment.So I guess the OP should say you also have a pencil. That should do it.The straight edge has no markings - it's not a ruler; you can't twirl it like a compass ... etc. Quote Link to comment Share on other sites More sharing options...
0 TimeSpaceLightForce Posted July 27, 2015 Report Share Posted July 27, 2015 (edited) starting with 3 points..connect P to diameter ends to make the points 4 & 5 on circumferenceconnect these points to opposite diameter ends to make intersection (point 6)..Draw an extended line from P thru 6 crossing diameter.. Edited July 27, 2015 by TimeSpaceLightForce redundant Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted July 27, 2015 Author Report Share Posted July 27, 2015 TSLF has it. Nicely put into words. Quote Link to comment Share on other sites More sharing options...
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Using only a straight edge, construct a perpendicular to the drawn diameter of a circle, from a point P outside the circle.
Reinserted image, which had disappeared from my media folder.
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