bonanova Posted February 25, 2014 Report Share Posted February 25, 2014 n! = 1 405 006 117 752 879 898 543 142 606 244 511 569 936 384 000 000 000 What is n? 3 divides n Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted February 25, 2014 Report Share Posted February 25, 2014 Doug Adams knows. Quote Link to comment Share on other sites More sharing options...
0 phil1882 Posted February 25, 2014 Report Share Posted February 25, 2014 42 Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted February 25, 2014 Author Report Share Posted February 25, 2014 SP got there first. Can either of you convince the skeptics? Quote Link to comment Share on other sites More sharing options...
0 Perhaps check it again Posted February 25, 2014 Report Share Posted February 25, 2014 On one level, that number can be shown to be between one of the numbers 40! and 44!, inclusive. The number in the puzzle written out ends in nine zeroes, so it has exactly none factors of 10. Then it has exactly nine factors of 5. Start listing consecutive multiples of 5, beginning with 5, and end until you get to a multiple that contains a cumulative ninth factor of 5: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, ... 5, 2*5, 3*5, 4*5, 5*5, 6*5, 7*5, 8*5 ====> Stop. If you have gone to 45 inclusive, you have gone too far, because that will provide a tenth factor of 5. Quote Link to comment Share on other sites More sharing options...
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bonanova
n! = 1 405 006 117 752 879 898 543 142 606 244 511 569 936 384 000 000 000
What is n?
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