Guest Posted March 20, 2008 Report Share Posted March 20, 2008 this was a year ago, but i'm not sure if this is correct, but you can try. (i can assure you that there is no 2) Is there a pattern for 4,1,1/2,1/4... post your answers, correct or not Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 20, 2008 Report Share Posted March 20, 2008 there is not a pattern Quote Link to comment Share on other sites More sharing options...
0 grey cells Posted March 20, 2008 Report Share Posted March 20, 2008 (edited) 4,1,1/2,1/4.... according to me , the alternate nos. are divided: eg.4/(1/2)=8 1/(1/4)=4 (1/2)/(1/4)=2 (1/4)/(1/4)=1 The results get divided by 2. Please correct me if I am wrong. Edited March 20, 2008 by grey cells Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 20, 2008 Report Share Posted March 20, 2008 (edited) Please correct me if I am wrong.4,1,1/2,1/4.... according to me , the alternate nos. are divided: eg.4/(1/2)=8 1/(1/4)=4 (1/2)/(1/4)=2 (1/4)/(1/4)=1 The results get divided by 2. I dont think thats the pattern cuz in order for there to be a pattern then you would have to be able to figure out more of the sequence. and from what i know "...." at the end of a sequence means theres more and you can figure it out."? Leaving the other numbers alone to use them when it gives the answer doesnt show any pattern. I agree with Jordanmax above, i dont think there is a pattern in it. If there is then theres prolly a really complicated formula for it that im too thick headed to see. Edited March 20, 2008 by Spyderz Quote Link to comment Share on other sites More sharing options...
0 grey cells Posted March 20, 2008 Report Share Posted March 20, 2008 I dont think thats the pattern cuz in order for there to be a pattern then you would have to be able to figure out more of the sequence. and from what i know "...." at the end of a sequence means theres more and you can figure it out."? I agree with you.But I have also filled in 2 more numbers(1/4,1/4)to continue the sequence.And it keeps the pattern running Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 20, 2008 Report Share Posted March 20, 2008 this was a year ago, but i'm not sure if this is correct, but you can try. (i can assure you that there is no 2) Is there a pattern for 4,1,1/2,1/4... post your answers, correct or not 4,1,1/2,1/4... 1,1/2,4,1/2,8 Divide the 2nd # by the 1st to get the 4th. Divide the 3rd by the 2nd to get the 5th. Divide the 4th by the 3rd to get the 6th... Continue this for the 7th and 8th Quote Link to comment Share on other sites More sharing options...
0 itachi-san Posted March 20, 2008 Report Share Posted March 20, 2008 I agree there is no pattern. Tanstaafl, it's never good if you are only using 1 example based on the given 4 numbers to conclude a series pattern. Also, 1/2 divided by 1 doesn't equal 1. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 21, 2008 Report Share Posted March 21, 2008 I agree there is no pattern. Tanstaafl, it's never good if you are only using 1 example based on the given 4 numbers to conclude a series pattern. Also, 1/2 divided by 1 doesn't equal 1. itchi-san, while I agree that I made a mistake in my division and spoiled the pattern, I do not agree with you that there is no pattern. Just because you cannot discern the pattern, doesn't mean that it isn't there. While on the subject, can you prove your negative? Of course not. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 21, 2008 Report Share Posted March 21, 2008 There is a pattern...I think. The sequence starts with N(0)=4, then to determine every number after N(0) you use this formula N(X)=N(0)/2^(X+1). this gives the results of N(0)=4, N(1)=1,N(2)=1/2,N(3)=1/4, N(4)=1/8.... Since the series can be shown using a formula there is in fact a pattern. Any thoughts? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 21, 2008 Report Share Posted March 21, 2008 There is a pattern...I think. The sequence starts with N(0)=4, then to determine every number after N(0) you use this formula N(X)=N(0)/2^(X+1). this gives the results of N(0)=4, N(1)=1,N(2)=1/2,N(3)=1/4, N(4)=1/8.... Since the series can be shown using a formula there is in fact a pattern. Any thoughts? im not getting your formula. is it just me or is it incorrect? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 21, 2008 Report Share Posted March 21, 2008 There is a pattern...I think. The sequence starts with N(0)=4, then to determine every number after N(0) you use this formula N(X)=N(0)/2^(X+1). this gives the results of N(0)=4, N(1)=1,N(2)=1/2,N(3)=1/4, N(4)=1/8.... Since the series can be shown using a formula there is in fact a pattern. Any thoughts? Looks great ... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 21, 2008 Report Share Posted March 21, 2008 im not getting your formula. is it just me or is it incorrect? The formula does work: N(0) = 4 N(1) = 4/(2^((1)+1))) = 4/(2^2) = 4/4 = 1 N(2) = 4/(2^((2)+1))) = 4/(2^3) = 4/8 = 1/2 N(3) = 4/(2^((3)+1))) = 4/(2^4) = 4/16 = 1/4 N(4) = 4/(2^((4)+1))) = 4/(2^5) = 4/32 = 1/8 Sorry for all the parentheses. I love parentheses for some reason. Nice work redsnuff. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 24, 2008 Report Share Posted March 24, 2008 None of those are correct. My dad and i tried square roots (sqrt(i... blablabla) i don't remember. KEEP TRYING! THIS PUZZLE IS ANNOWING ME! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 24, 2008 Report Share Posted March 24, 2008 Modifications. the pattern is 2,1/2,1/4,1/8... it has nothing to do with exponents. Remember, 0 is still a number don't think that the answer is 2^1,2^(1/2)... I am sure that that is not the answer Quote Link to comment Share on other sites More sharing options...
0 grey cells Posted March 24, 2008 Report Share Posted March 24, 2008 Modifications. the pattern is 2,1/2,1/4,1/8... it has nothing to do with exponents. Remember, 0 is still a number don't think that the answer is 2^1,2^(1/2)... I am sure that that is not the answer 2 is the starting number. From the next number , i.e. , 1/2 we can proceed in this manner:Dividing the first number by second number to get the result as "2". (1/2)/(1/4)=2 (1/4)/(1/8)=2 (1/8)/(1/16)=2 . . . . . This sounds simple But there is a definite pattern to it.And it was a pattern you asked . Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2008 Report Share Posted March 25, 2008 2 is the starting number. From the next number , i.e. , 1/2 we can proceed in this manner:Dividing the first number by second number to get the result as "2". (1/2)/(1/4)=2 (1/4)/(1/8)=2 (1/8)/(1/16)=2 . . . . . This sounds simple But there is a definite pattern to it.And it was a pattern you asked . Actually You are notr exacly giving a pattern...in your case, you are considering 2 as a out of the series number...I cant find any pattern in it.. Quote Link to comment Share on other sites More sharing options...
0 grey cells Posted March 25, 2008 Report Share Posted March 25, 2008 Actually You are notr exacly giving a pattern...in your case, you are considering 2 as a out of the series number...I cant find any pattern in it.. I too could not find any other pattern . So I decided upon leaving out 2. You are right , leaving out a number does not denote a pattern . But it was the closest thing I could find , so I just posted my answer. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2008 Report Share Posted March 25, 2008 I think ent474 needs to clarify the puzzle. The original post clearly states 2 is not part of the sequence. Then when an answer was posted to the original sequence he insisted it was incorrect and he seems to have posted a modification changing the original sequence to include 2 and not 4. At this point I'm not even sure what we're trying to solve anymore. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2008 Report Share Posted March 25, 2008 2 1/2 1/4 1/8 sure this is still wrong. OP said " i can assure you there is no 2" Is this to do with egyptian fractions loaves and fishes is ringing a bell, but so did Quasimodo Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2008 Report Share Posted March 27, 2008 erase the whole original post from your mind the pattern is 2,1/2,1/4,1/8 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2008 Report Share Posted March 27, 2008 I have the solution (thanks to jesusfreak) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2008 Report Share Posted March 27, 2008 Somehow the spoiler didn't show up. Here is the solution.. The original pattern was 4,1,1/2,1/4.. The new pattern is 2,1/2,1/4,1/8.. See the similarity, just divide by 2 Based on jesusfreak's solution, the answer would be F(X) = (2*F(0))/ (2^(X+2)) so F(0)=2 F(1)=1/2 F(2)=1/4 F(3)=1/8 and F(4)=1/16 F(5)=1/32 .... Quote Link to comment Share on other sites More sharing options...
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this was a year ago, but i'm not sure if this is correct, but you can try.
(i can assure you that there is no 2)
Is there a pattern for 4,1,1/2,1/4...
post your answers, correct or not
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