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this was a year ago, but i'm not sure if this is correct, but you can try.

(i can assure you that there is no 2)

Is there a pattern for 4,1,1/2,1/4...

post your answers, correct or not

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Posted · Report post

:rolleyes: there is not a pattern
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Posted (edited) · Report post

4,1,1/2,1/4....

according to me , the alternate nos. are divided:

eg.4/(1/2)=8

1/(1/4)=4

(1/2)/(1/4)=2

(1/4)/(1/4)=1

The results get divided by 2.B))

Please correct me if I am wrong.

Edited by grey cells
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Posted (edited) · Report post

Please correct me if I am wrong.

4,1,1/2,1/4....

according to me , the alternate nos. are divided:

eg.4/(1/2)=8

1/(1/4)=4

(1/2)/(1/4)=2

(1/4)/(1/4)=1

The results get divided by 2.B))

I dont think thats the pattern cuz in order for there to be a pattern then you would have to be able to figure out more of the sequence. and from what i know "...." at the end of a sequence means theres more and you can figure it out."? Leaving the other numbers alone to use them when it gives the answer doesnt show any pattern. I agree with Jordanmax above, i dont think there is a pattern in it. If there is then theres prolly a really complicated formula for it that im too thick headed to see.

Edited by Spyderz
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Posted · Report post

I dont think thats the pattern cuz in order for there to be a pattern then you would have to be able to figure out more of the sequence. and from what i know "...." at the end of a sequence means theres more and you can figure it out."?

I agree with you.But I have also filled in 2 more numbers(1/4,1/4)to continue the sequence.And it keeps the pattern running

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Posted · Report post

this was a year ago, but i'm not sure if this is correct, but you can try.

(i can assure you that there is no 2)

Is there a pattern for 4,1,1/2,1/4...

post your answers, correct or not

4,1,1/2,1/4... 1,1/2,4,1/2,8

Divide the 2nd # by the 1st to get the 4th. Divide the 3rd by the 2nd to get the 5th. Divide the 4th by the 3rd to get the 6th... Continue this for the 7th and 8th

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Posted · Report post

I agree there is no pattern.

Tanstaafl, it's never good if you are only using 1 example based on the given 4 numbers to conclude a series pattern. Also, 1/2 divided by 1 doesn't equal 1.

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Posted · Report post

I agree there is no pattern.

Tanstaafl, it's never good if you are only using 1 example based on the given 4 numbers to conclude a series pattern. Also, 1/2 divided by 1 doesn't equal 1.

itchi-san, while I agree that I made a mistake in my division and spoiled the pattern, I do not agree with you that there is no pattern. Just because you cannot discern the pattern, doesn't mean that it isn't there. While on the subject, can you prove your negative? Of course not.

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Posted · Report post

There is a pattern...I think.

The sequence starts with N(0)=4, then to determine every number after N(0) you use this formula N(X)=N(0)/2^(X+1).

this gives the results of N(0)=4, N(1)=1,N(2)=1/2,N(3)=1/4, N(4)=1/8....

Since the series can be shown using a formula there is in fact a pattern. Any thoughts?

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Posted · Report post

There is a pattern...I think.

The sequence starts with N(0)=4, then to determine every number after N(0) you use this formula N(X)=N(0)/2^(X+1).

this gives the results of N(0)=4, N(1)=1,N(2)=1/2,N(3)=1/4, N(4)=1/8....

Since the series can be shown using a formula there is in fact a pattern. Any thoughts?

im not getting your formula. is it just me or is it incorrect? :huh:

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Posted · Report post

There is a pattern...I think.

The sequence starts with N(0)=4, then to determine every number after N(0) you use this formula N(X)=N(0)/2^(X+1).

this gives the results of N(0)=4, N(1)=1,N(2)=1/2,N(3)=1/4, N(4)=1/8....

Since the series can be shown using a formula there is in fact a pattern. Any thoughts?

Looks great ...

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Posted · Report post

im not getting your formula. is it just me or is it incorrect? :huh:

The formula does work:

N(0) = 4

N(1) = 4/(2^((1)+1))) = 4/(2^2) = 4/4 = 1

N(2) = 4/(2^((2)+1))) = 4/(2^3) = 4/8 = 1/2

N(3) = 4/(2^((3)+1))) = 4/(2^4) = 4/16 = 1/4

N(4) = 4/(2^((4)+1))) = 4/(2^5) = 4/32 = 1/8

Sorry for all the parentheses. I love parentheses for some reason.

Nice work redsnuff.

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Posted · Report post

None of those are correct. My dad and i tried square roots (sqrt(i... blablabla) i don't remember.

KEEP TRYING! THIS PUZZLE IS ANNOWING ME!

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Posted · Report post

Modifications.

the pattern is 2,1/2,1/4,1/8...

it has nothing to do with exponents.

Remember, 0 is still a number

don't think that the answer is 2^1,2^(1/2)...

I am sure that that is not the answer

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Posted · Report post

Modifications.

the pattern is 2,1/2,1/4,1/8...

it has nothing to do with exponents.

Remember, 0 is still a number

don't think that the answer is 2^1,2^(1/2)...

I am sure that that is not the answer

2 is the starting number.

From the next number , i.e. , 1/2 we can proceed in this manner:Dividing the first number by second number to get the result as "2".

(1/2)/(1/4)=2

(1/4)/(1/8)=2

(1/8)/(1/16)=2

.

.

.

.

.

This sounds simple But there is a definite pattern to it.And it was a pattern you asked . :)

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Posted · Report post

2 is the starting number.

From the next number , i.e. , 1/2 we can proceed in this manner:Dividing the first number by second number to get the result as "2".

(1/2)/(1/4)=2

(1/4)/(1/8)=2

(1/8)/(1/16)=2

.

.

.

.

.

This sounds simple But there is a definite pattern to it.And it was a pattern you asked . :)

Actually You are notr exacly giving a pattern...in your case, you are considering 2 as a out of the series number...I cant find any pattern in it..

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Posted · Report post

Actually You are notr exacly giving a pattern...in your case, you are considering 2 as a out of the series number...I cant find any pattern in it..

I too could not find any other pattern . So I decided upon leaving out 2. You are right , leaving out a number does not denote a pattern . But it was the closest thing I could find , so I just posted my answer.

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I think ent474 needs to clarify the puzzle. The original post clearly states 2 is not part of the sequence. Then when an answer was posted to the original sequence he insisted it was incorrect and he seems to have posted a modification changing the original sequence to include 2 and not 4. At this point I'm not even sure what we're trying to solve anymore.

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Posted · Report post

2

1/2

1/4

1/8

sure this is still wrong. OP said " i can assure you there is no 2"

Is this to do with egyptian fractions loaves and fishes is ringing a bell, but so did Quasimodo

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Posted · Report post

erase the whole original post from your mind

the pattern is 2,1/2,1/4,1/8

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Posted · Report post

I have the solution (thanks to jesusfreak)

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Somehow the spoiler didn't show up. Here is the solution..

The original pattern was

4,1,1/2,1/4..

The new pattern is

2,1/2,1/4,1/8..

See the similarity, just divide by 2

Based on jesusfreak's solution, the answer would be

F(X) = (2*F(0))/ (2^(X+2))

so

F(0)=2

F(1)=1/2

F(2)=1/4

F(3)=1/8

and

F(4)=1/16

F(5)=1/32 ....

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