curr3nt
-
Posts
2840 -
Joined
-
Last visited
-
Days Won
1
Content Type
Profiles
Forums
Events
Gallery
Blogs
Everything posted by curr3nt
-
-
-
Hmm...both of them using three thumbs up smilies could mean smoth is planning on taking action on flamebirde (3rd in the roster) or me (C3). With Cat confirming. smoth had 7 ! and Cat only had 3. maurice is the 7th in the roster so maybe they are suggesting getting maurice to go after the 3. How deep does the conspiracy go?
-
"go goodies" is an EDM thing. smoth wants us to think EDM is secretly mentoring him. Cat is now countering the EDM mentor claim which is a suprise attack seeing as how it is only N1. I'm curious to see how it plays out. And you are wrong mew. I trust you, mboon and lancelot.
-
-
You want the answers MiKi?
-
If I had any feelings you might have hurt them.
-
You missed a C.
-
NIGHT 1 WILL END AT 11PM EST (-5 GMT) What day?
-
MissKitten can take my spot. She might live longer against maurice.
-
Hmm... you all do not care about f(n). You are just trying to sum up all the combinations that is <= n. So for s(10)... 1+2+3 <= 10 yields 2^3-1 = 7 combinations. What is the equation then for adding 5 and 8? Adding 5 means 2^4-1 combinations but 2^3-1 have already been used so we have (2^4-1) - (2^3-1) = 8 How do you determine how many are over 10 with an equation? { 5, 5+3, 5+2, 5+1, 5+3+2, 5+3+1, 5+2+1 } = 7 Seems he is leading to s(10) = 2^3-1 + s(10-5) + s(10-8) s(5) : 1+2 <= 5 : 2^2-1 + s(5-3) + s(5-5) s(2) : 1 < 2 : 2^1-1 + s(2-2) if... 2^2-1 = { 5+2+1, 5+2, 5+1 } s(5-3) ....2^1-1 = { 5+3+1 } ....s(2-2) = { 5+3+2 } s(5-5) = { 5+3 } then where is the { 5 } ? And since s(2) = 2 how does s(10-8) = 3 for the three combinations with 8? It is looking like 2^3 - 1 + s(10-5) + 1 + s(10-8) + 1 Since s(10-5) actually covers all the combinations of 5 with 1+2+3 but doesn't include 5 by itself. Same with s(10-8) covers the combinations of 1+2 that can go with 8 but not 8 by itself.
-
If I die N1 maurice is a baddie...
-
-
-
??? I do not understand where your equation comes from...
-
I can pretend to not know what I'm doing.
-
Not sure if helpful but there seems to be a pattern in getting the number of sum equations.
-
gah...I can't get it to display...
-
The questions will be marked wrong until they are true. #1 can't be A or B. If A then #1 answer would have to be B to be correct. If B then #2 would have to be the first question with the answer B but #1 would actually be the first with the answer B. So it has to be C, D or E. Check one of them and then make the corresponding question a B. You'll see that #1 is now marked true. You could have the correct answer for a question set but it will be flagged incorrect until the related questions have been answered correctly.
-
Solved it. That was a mess...but fun. I got a correct answer for #1
-
It is on wikipedia... http://en.wikipedia.org/wiki/Purple_squirrel
-
-
I'm smarter than the average bear.
-
Just because it isn't what you wanted doesn't mean it doesn't work.
-
