BUICK
if BUICK - 2, first 2 letters are BU. SNACK-0 eliminated CK, QUICK and QUACK (both 1) prove that I and A cannot be third. We are left with Q or U being correct. if BUICK has 2, the B and U are both correct because ICK is not.
if BUICK - 1, the second letter is U. From the same logic above, ICK is eliminated. Q or U must be correct. if Q is correct, then B cannot be the first letter, so if BUICK-1, U must be the second letter.
if BUICK - 0, the first letter is Q. From the same logic above, Q or U must be correct so if U is not, Q must be the first letter.