Not sure!!!!
Take away all the glassess first (since i have to use it only once).
Let me have the glassess as g1,g2,g3,g4
pour one quater the amount of g2 to g1 say g1+g2/4
same half and three fourth of 3rd and 4th respectively
so the first glass will now have g1+g2/4+g3/2+g3*3/4 (Assuming we are able to measure g2/4 , g3/2 or g3*3/4)
now weigh that glass if the weight gonna be
CASE 1 :(A+X)+A/4+A/2+3A/4 then g1 is poisoned
CASE 2: A+(A+X)/4+A/2+3A/4 then g2 is poisoned
CASE 3 : A+A/4+(A+X)/2+3A/4 then g3 is poisoned
CASE 4: A+A/4+A/2+3(A+X)/4 then g4 is poisoned