I think the answer is :

here is how i figured my answer out:

Explaination is below:

all i was trying to do is to rule out every answer which is not correct due to contest(who wouldn't

),and i begin with the 3rd question,suppose the answer is A,B,C,D, and here we go:

for #1:if 3rd=A, then 1st=D; then 2nd=B;then 4th=A, which indicates the number of questions which have D

B as the correct answer is:

</STRONG>A. 0

B. 2

C. 3

D. 1

according to what we got now(which is C,D,B,C for questions 1,2,3,4 ), we would certainly put D to question 5(we do have only one D in C,D,B,C )then we will immediately find out that at the moment we got two Ds, which violates our agreement with question 4 where we put a C(

**4. The number of questions which have D as the correct answer is:**

A. 3

B. 2

C. 1

D. 0 )

BUT if we change the answer to the 5th question to B, which indicates 2 B in all the answers(we got one in the last four questions and, the last one just play a role of duo), we can find all the answers just fit perfectly.

**So with no doubt, the answer is** **C,D,B,C,B. **