[Guest]

Keep making mistakes - where did I go wrong?

  PLAYED WON LOST DRAWN FOR AGAINST POINTS

A  3                           3      5

B              0    2    5     3      4

C  2      0              6     8

D  3                           8      0

[/codebox]

2 for a win

1 for a draw

Not all games played yet

[kingofpain]

Keep making mistakes - where did I go wrong?

A 3 2 0 1 3 5
B 3 1 0 2 5 3 4
C 2 0 6 8
D 3 8 0

  PLAYED WON LOST DRAWN FOR AGAINST POINTS

Sum of games played cannot be odd.

[Guest]

Keep making mistakes - where did I go wrong?

A 3 2 0 1 3 5
B 3 1 0 2 5 3 4
C 2 0 6 8
D 3 8 0

 PLAYED WON LOST DRAWN FOR AGAINST POINTS

Sum of games played cannot be odd.

Again it's not a completed tounament and fixtures are to be played yet - Where is the mistake?

[kingofpain]

Again it's not a completed tounament and fixtures are to be played yet - Where is the mistake?

Again, it doesn't matter. Unless there are more teams that are not shown in this table, the sum of number of games played by each team MUST BE even

[Guest]

Again, it doesn't matter. Unless there are more teams that are not shown in this table, the sum of number of games played by each team MUST BE even

Again - So a sheet is being filled out and while doing so and before completing an error is spotted - can you spot it?

[Guest]

To have 4 points, and having 2 draws, Team B must have played 3 games, so the mistake could be in the points there, because not all the other teams can have played 3 and C played 2, if each team is only playing each other team once. So the mistake could be in the games played for C aswell.

Nice riddle LIS. Really has me thinking.

Edited June 16, 2008 by RoopthePoop

[Guest]

I think that the "For" and "Against" columns are wrong for C. If there are only four teams, there are a total of three wins and three ties between A and B. D has three losses since they have 0 points, meaning that C must have tied both games they played. As such, they should have the same number of goals for and against.

[Guest]

Not that much input, (3 attempts - inc 1 doubter of the topic)

Nice riddle LIS. Really has me thinking.

To have 4 points, and having 2 draws, Team B must have played 3 games, so the mistake could be in the points there, because not all the other teams can have played 3 and C played 2, if each team is only playing each other team once. So the mistake could be in the games played for C aswell.

I think that the "For" and "Against" columns are wrong for C. If there are only four teams, there are a total of three wins and three ties between A and B. D has three losses since they have 0 points, meaning that C must have tied both games they played. As such, they should have the same number of goals for and against.

Not correct - sorry, maybe these are harder than I thought, it's really a logic problem.

Try to work out the scores for each game, that os easier for me to check also

Perhaps some are finding this sort of problem as needing too much attention, it can be noted and done on the bus ... anyway no rush!

[grey cells]

A 3 2 0 [b]1[/b] 3 5
B 3 1 0 [b]2 [/b] 5 3 4
C 2 0 1 [b]1 [/b] 6 8 1
D [b]3 [/b] 0 3 0 8 0

  PLAYED WON LOST DRAWN FOR AGAINST POINTS

If D has played 3 matches and has 0 points then he must have lost all 3 .

Now B has 2 drawn games , one against A and the other against C(D hasn't won or drawn any)

STATEMENTS:

1. B has played 3 games(A[Drawn] C[Drawn] D[Won]).

2.A has played 3 games(B[Drawn] C[won] D[won]).

3.D has played 3 games(lost against A B C)

4.C has played 2 games(B[drawn] A[lost]) . C couldn't have lost to D as D has 0 points.

So statements 3 and 4 do not tally.

Great puzzle LIS and a fun one too.

Edited June 18, 2008 by grey cells

[Guest]

A 3 2 0 [b]1[/b] 3 5
B 3 1 0 [b]2 [/b]5 3 4
C 2 0 1 [b]1 [/b]6 8 1
D [b]3 [/b]0 3 0 8 0

 PLAYED WON LOST DRAWN FOR AGAINST POINTS

If D has played 3 matches and has 0 points then he must have lost all 3 .

Now B has 2 drawn games , one against A and the other against C(D hasn't won or drawn any)

STATEMENTS:

1. B has played 3 games(A[Drawn] C[Drawn] D[Won]).

2.A has played 3 games(B[Drawn] C[won] D[won]).

3.D has played 3 games(lost against A B C)

4.C has played 2 games(B[drawn] A[lost]) . C couldn't have lost to D as D has 0 points.

So statements 3 and 4 do not tally.

Great puzzle LIS and a fun one too.

Thanks GC, nice to know someone is trying- You have three statements correct!

Would like to see if anyone has worked out the scores for a double kudos and a pancake! - have to come to netherlands for the pancake ... which reminds me BN wheres that pancake answer!

[Guest]

Other than the missing game against D, I can't find anything wrong with the data.

As I figured it, the scores are something like the following:

A v. B: 0-0

A v. C: 5-3

A v. D: [<=5]-0

For: [<=10] Against: 3

B v. A: 0-0

B v. C: 3-3

B v. D: 2-0

For: 5 Against: 3

C v. A: 3-5

C v. B: 3-3

For: 6 Against: 8

D v. A: 0-[6-x]

D v. B: 0-2

D v. ?: [<x]-x

For: [<x] Against: 8

Sorry if the formatting is a little weird: the brackets [] signify unknown values.

Unless I've overlooked something obvious, I don't see a contradiction; it all seems to work out...

[Guest]

Other than the missing game against D, I can't find anything wrong with the data.

As I figured it, the scores are something like the following:

A v. B: 0-0

A v. C: 5-3

A v. D: [<=5]-0

For: [<=10] Against: 3

B v. A: 0-0

B v. C: 3-3

B v. D: 2-0

For: 5 Against: 3

C v. A: 3-5

C v. B: 3-3

For: 6 Against: 8

D v. A: 0-[6-x]

D v. B: 0-2

D v. ?: [<x]-x

For: [<x] Against: 8

Sorry if the formatting is a little weird: the brackets [] signify unknown values.

Unless I've overlooked something obvious, I don't see a contradiction; it all seems to work out...

You obviously know the error - and you are almost there on the scores too