Hotel

[Guest]

The second guest is left in the lobby therefore has a room to himself.

[Guest]

Of the 13 people who want their own rooms, 2 are a couple. And the couple gets their own room.

[Guest]

Here is how it works

1 - Guest 1 & 2 (for the time being)

2 - Guest 3

3 - Guest 4

4 - Guest 5

5 - Guest 6

6 - Guest 7

7 - Guest 8

8 - Guest 9

9 - Guest 10

10 - Guest 11

11 - Guest 12

12 - Guest 2

Oh - thought it worked - guess not - sorry - not sure if this is right or not?

Edited September 24, 2008 by GabrownzFan

[Guest]

Rookie you always post these "not possible" puzzles and I hate them. Give me a puzzle you can solve

[Guest]

Hotel - Back to the Logic Puzzles

13 men came into a hotel with 12 rooms and everybody wanted his own room. The bellboy solved this problem.

He asked the thirteenth guest to wait a moment with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, ... and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to empty room number 12.

How can everybody have his own room?

Hotel - solution

Of course, it is impossible. Into the second room should have gone the 2nd guest, because the 13th guest was waiting in room number 1.

This quiz is similar to this one:

"Horses": if you had nine boxes and you had to fit ten horses in them how would you do it? posted by xXspygirlXx

http://brainden.com/forum/index.php?showto...%20box&st=0

[peace*out]

What if they didn't come in at the same time??

guest 1 to room 1

guest 2 to room 2

guest 3 to room 3

ect..........

when you get to the thirteenth guest, guest one has checked out, so he get's a room!!

or..........

Who ever said 2 of them wern't a couple??

2 twins, or a double!!

[Guest]

Hotel - Back to the Logic Puzzles

13 men came into a hotel with 12 rooms and everybody wanted his own room. The bellboy solved this problem.

He asked the thirteenth guest to wait a moment with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, ... and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to empty room number 12.

How can everybody have his own room?

Hotel - solution

Of course, it is impossible. Into the second room should have gone the 2nd guest, because the 13th guest was waiting in room number 1.

This is possible when you assume the rooms are numbered 1-12. A lot of hotels do not have a room #13, since it is considered 'unlucky'. therefore they skip a number of use a number twice even. This is the case here. The first and second guest were together so that no one would figure out that they actually had the thirteenth room.

[Guest]

This is possible when you assume the rooms are numbered 1-12. A lot of hotels do not have a room #13, since it is considered 'unlucky'. therefore they skip a number of use a number twice even. This is the case here. The first and second guest were together so that no one would figure out that they actually had the thirteenth room.

I understand what you are saying, but you are changing the story. It states that 12 rooms are available; not that the rooms 1-12 are available. If the ladder were the riddle I would have to concede your point; which is a valid observation. Unfortunately, it does not apply in this scenario.

[Guest]

it says "his". maybe one of the people is a "her" who can stay with with one of the other males! <_<

[Guest]

they write "room" on thirteen different pieces of paper and each keep one.

[Guest]

That's easy one of the 13 people to walk into the hotel was the bellboy!!

[Guest]

guest two didn't get much of a mention

[Guest]

one person may be pregnant..baby too may be counted as person but doesn't need a separate room....howz it??

[Guest]

its do easy, DOES ANYONE REMEMBER HOTELS HAVE BATHROOMS