gavinksong Posted January 15, 2015 Report Share Posted January 15, 2015 This is a follow-up to do not know the answer to this problem. How many lights are necessary to completely illuminate a convex solid in N dimensions? Same conditions as before: We are working in an otherwise empty N-dimensional space. The lights are point sources. The solid is illuminated at every point on its surface where a straight line can be drawn uninterrupted between it and a light source. Let me also add: Lights cannot be placed "at infinity". Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted January 15, 2015 Report Share Posted January 15, 2015 N+1. Add a dimension, add a light. Point - 1 light Line - 2 lights. Circle - 3 lights Sphere - 4 lights Hyper sphere - 5 lights , but I can't draw the picture. Etc... Quote Link to comment Share on other sites More sharing options...
0 gavinksong Posted January 16, 2015 Author Report Share Posted January 16, 2015 N+1. Add a dimension, add a light. Point - 1 light Line - 2 lights. Circle - 3 lights Sphere - 4 lights Hyper sphere - 5 lights , but I can't draw the picture. Etc... Can you prove it? Quote Link to comment Share on other sites More sharing options...
0 harey Posted January 16, 2015 Report Share Posted January 16, 2015 Point - 1 light Can you prove it? I hesitate between 1 and 2... Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted January 17, 2015 Report Share Posted January 17, 2015 @gavinksong No, I can't. For solids it just seems intuitive. For points and lines, I am ready to change my answer. Points and lines have no surfaces to illuminate. In that sense they need 0 lights. Shining 0 lights on a point or line suffices to leave no surface un-illuminated. Quote Link to comment Share on other sites More sharing options...
0 harey Posted January 26, 2015 Report Share Posted January 26, 2015 (edited) Not so quickly... If we need (in 3D) four lights for a sphere, a cylinder can be illuminated by three lights only. (I spent a long time to find a way to show that the edges can be smoothened and still illuminated until I consulted http://en.wikipedia.org/wiki/Convex_body and realized that a cylinder is a convex solid). For a cone, two lights are enough. What bothers me at most: Consider a unit cube in the xyz coordinates and a line (0;0;0) - (1;1;1). If we need 0 lights to illuminate a point or a line, the whole cube would be illuminated by just two lights placed on this line just slightly outside the cube. Edited January 26, 2015 by harey Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted January 26, 2015 Report Share Posted January 26, 2015 @harey, all good points. I totally agree. The answers given previous to your post apply only if we interpret the OP to ask How many lights are necessary to completely illuminate any/a general convex solid in N dimensions? Otherwise, we can enumerate special cases, as you have. And a complete answer would be a complete enumeration. These thoughts suggest what I think is an interesting question: for each N, find an example of a convex solid that can be illuminated with the fewest lights. So far we have, N=0 point. zero. (a point may not qualify as a solid) N=1 line segment. zero (a line or line segment may not qualify as a solid) N=2 triangle. two. (a triangle may not qualify as a solid.) N=3 two (truncated cone, cube lighted outside two opposite corners) N=4 three? N=5 four? . N=Q Q-1? We could eliminate 0, 1 and 2 if we require the object to have non-zero volume. Then we wouldn't have to debate whether dots, lines and circles are solids. Quote Link to comment Share on other sites More sharing options...
0 harey Posted January 27, 2015 Report Share Posted January 27, 2015 These thoughts suggest what I think is an interesting question: for each N, find an example of a convex solid that can be illuminated with the fewest lights. That's the start to the original question What bothers me with points and lines: We do not illuminate an object as such, we illuminate it's surfaces. (Already a problem with a sphere and alike: in this case, we may not consider the sphere has one surface, but infinity.) If a surface is illuminated, does it imply that it's edges and vertexes are illuminated, too? One answer would be that this question does not have a sense, but it seems a little week as argument. Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted January 27, 2015 Report Share Posted January 27, 2015 The solid is illuminated at every point on its surface where a straight line can be drawn uninterrupted between it and a light source. Quote Link to comment Share on other sites More sharing options...
0 harey Posted January 29, 2015 Report Share Posted January 29, 2015 This assumes that a point is (at least partially) illuminated if a straight line can be drawn uninterrupted between it and a light source. Quote Link to comment Share on other sites More sharing options...
0 gavinksong Posted February 13, 2015 Author Report Share Posted February 13, 2015 A point, whether or not it is on a surface or on an edge or a vertex, is illuminated if a straight line can be drawn uninterrupted between it and a light source. Thus, for example, in the three-dimensional case, a cube could be fully illuminated by two lights. Like bonanova said, you may assume that the OP is asking for the fewest number of lights required to guarantee that any convex solid can be fully illuminated by some positioning of the light sources relative to the solid. Quote Link to comment Share on other sites More sharing options...
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gavinksong
This is a follow-up to do not know the answer to this problem.
How many lights are necessary to completely illuminate a convex solid in N dimensions?
Same conditions as before:
Let me also add:
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