BMAD Posted August 11, 2014 Report Share Posted August 11, 2014 On a standard qwerty keyboard, how many "2-letter adjacency words" can be formed? Adjacent implies that the word must be formed by two distinct letters that are next to each other on a keyboard (corners count) Any two letters, for the sake of argument, form a two-letter word. Quote Link to comment Share on other sites More sharing options...
0 Perhaps check it again Posted August 12, 2014 Report Share Posted August 12, 2014 (edited) Actually, I'm going to have to amend my answer to the revised answer of: 110 because I left out the obvious dual combinations. ****** Actually, bonanova, your keyboard, I'm sure, does not look quite like that. For instance, the "Q" key is not perfectly adjacent diagonally to the "S" key. And, for instance, the "W" key is not perfectly adjacent diagonally to the "D" key. To go from Q to S in the shortest path, you must pass through either A or W. And to go from W to D in the shortest path, you must pass through either S or E. You just look more closely and you'll see that the top row is not in line with the middle row, I'm sure. Edited August 12, 2014 by Perhaps check it again Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted August 11, 2014 Report Share Posted August 11, 2014 Diagonal adjacency permitted? Only A-Z characters? What does "corners count" mean? Quote Link to comment Share on other sites More sharing options...
0 BMAD Posted August 11, 2014 Author Report Share Posted August 11, 2014 Diagonal adjacency permitted? Only A-Z characters? What does "corners count" mean? corners count means that diagonal adjacency is permitted. And yes, only letter characters. Quote Link to comment Share on other sites More sharing options...
0 Perhaps check it again Posted August 12, 2014 Report Share Posted August 12, 2014 bottom row --> 6 middle row --> 8 top row -------> 9 bottom row to middle row --> 14 middle row to top row -------> 18 -------------------------------------------- 6 + 8 + 9 + 14 + 18 = 55 Answer: 55 Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted August 12, 2014 Report Share Posted August 12, 2014 126My keyboard looks like this.q w e r t y u i o p a s d f g h j k l z x c v b n m Because of the offset of the bottom row from the other two, there are only diagonal pairs. Between the top and middle rows there are orthogonal and diagonal pairs. Thus:top row (18): qw we er rt ty yu ui io op po oi iu uy yt tr re ew wq top-middle row (52): qa qs aq aw wa ws wd sq sw se es ed ef dw de dr rd rf rg fe fr ft tf tg th gr gt gy yg yh yj ht hy hu uh uj uk jy ju ji ij ik il ku ki ko ok ol li lo lp pl middle row (16): as sd df fg gh hj jk kl lk kj jh hg gf fd ds sa middle- bottom row (28): az za zs sz sx xs xd dx dc cd cf fc fv vf vg gv gb bg bh hb hn nh nj jn jm mj mk km bottom row (12): zx xc cv vb bn nm mn nb bv vc cx xz Quote Link to comment Share on other sites More sharing options...
Question
BMAD
On a standard qwerty keyboard, how many "2-letter adjacency words" can be formed?
Adjacent implies that the word must be formed by two distinct letters that are next to each other on a keyboard (corners count)
Any two letters, for the sake of argument, form a two-letter word.
Link to comment
Share on other sites
5 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.