Perhaps check it again Posted April 7, 2014 Report Share Posted April 7, 2014 (edited) You will use exactly twelve of the numbers 0.7 and exactly four of the numbers 0.6. Or, you can just type ".7" and ".6," respectively, if you wish. Concatenation of the sevens and sixes (mixed or matched) is not allowed). No other numbers are to be used. You can use unlimited plus signs. An unlimited number of parentheses can be used for both grouping and for multiplication. No other symbols or operations may be used. Put these together to form an expression that gives the maximum value. Here are two examples of the forms: Example 1) (0.7 + 0.7 + 0.7 + 0.7 + 0.7 + 0.7)(0.7 + 0.7 + 0.7 + 0.7 + 0.7 + 0.7)(0.6 + 0.6 + 0.6 + 0.6) = (4.2)(4.2)(2.4) = 42.336 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Example 2) (.7 + .7)(.7 + .7)(.7 + .7)(.7 + .7)(.7 + .7)(.7 + .7)(.6 + .6)(.6 + .6) = [(1.4)^6](1.2)(1.2) = 10.843 (approximately) (Let me know if I made any errors, please.) Edited April 7, 2014 by Perhaps check it again Quote Link to comment Share on other sites More sharing options...
0 Pickett Posted April 7, 2014 Report Share Posted April 7, 2014 (edited) (.7+.7+.7+.6)(.7+.7+.7+.6)(.7+.7+.7+.6)(.7+.7+.7+.6) = 53.1441 Edited April 7, 2014 by Pickett 1 Quote Link to comment Share on other sites More sharing options...
0 BMAD Posted April 8, 2014 Report Share Posted April 8, 2014 I believe Pickett has it Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted April 8, 2014 Report Share Posted April 8, 2014 Pickett has my vote Quote Link to comment Share on other sites More sharing options...
Question
Perhaps check it again
You will use exactly twelve of the numbers 0.7 and exactly four of the numbers 0.6.
Or, you can just type ".7" and ".6," respectively, if you wish.
Concatenation of the sevens and sixes (mixed or matched) is not allowed).
No other numbers are to be used.
You can use unlimited plus signs. An unlimited number of
parentheses can be used for both grouping and for
multiplication. No other symbols or operations may be used.
Put these together to form an expression that gives the maximum
value.
Here are two examples of the forms:
Example 1)
(0.7 + 0.7 + 0.7 + 0.7 + 0.7 + 0.7)(0.7 + 0.7 + 0.7 + 0.7 + 0.7 + 0.7)(0.6 + 0.6 + 0.6 + 0.6) =
(4.2)(4.2)(2.4) =
42.336
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Example 2)
(.7 + .7)(.7 + .7)(.7 + .7)(.7 + .7)(.7 + .7)(.7 + .7)(.6 + .6)(.6 + .6) =
[(1.4)^6](1.2)(1.2) =
10.843 (approximately)
(Let me know if I made any errors, please.)
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