BMAD Posted August 22, 2013 Report Share Posted August 22, 2013 From a book, a number of consecutive pages are missing. The sum of the page numbers of these pages is 9808. Which pages are missing? Quote Link to comment Share on other sites More sharing options...

0 Anza Power Posted August 22, 2013 Report Share Posted August 22, 2013 The pages are in the range 291-322 Quote Link to comment Share on other sites More sharing options...

0 witzar Posted August 22, 2013 Report Share Posted August 22, 2013 just one page (number 9808) is missing Quote Link to comment Share on other sites More sharing options...

0 dgreening Posted August 22, 2013 Report Share Posted August 22, 2013 If an even number of pages are removed the sum of the missing page numbers [9808] divided by the number of pages missing would have a fractional portion of 0.5 If an odd number of pages are removed the sum of the missing page numbers [9808] divided by the number of pages missing would have a fractional portion of 0. A trivial solution exist for the removal of a single page [number 9808]. When divided by 1, the result is 9808. If we ignore this [the problem states that "pages" are missing]. If we define N as the number of pages missing then we must test the possible number of missing pages using the following: Frac [9808/ N] = 0.5 where N is an even number; or 0.0 where N is an off number testing for up to 100 pages missing there is only 1 value of N that satisfies this criteria For N = 32 9808/ 32 = 306.5 This tells us that 32 pages are missing and the average value of these page numbers is 306.5 Taking 16 integers values below and 16 integer values above 306.5 gives us a range of pages 291 thru 322 The sum of these pages = 9808 Quote Link to comment Share on other sites More sharing options...

0 witzar Posted August 22, 2013 Report Share Posted August 22, 2013 (edited) Let p be the first page and let n be the number of pages. We have to solve the following equation: n*(2p+n-1)/2 = 9808 = 613*16 or equivalent one: n*(2p+n-1) = 613*2^5 in positive integers (note that 613 is prime). If n is a multiple of 613, then left side is obviously bigger than right side, so n has to be equal to 2^k for some 0<=k<=5. In such case we can divide both sides by n, and see that left side becomes odd and right side stays even, unless n=1 or n=32. This leads to two mentioned above solutions. Edited August 22, 2013 by witzar Quote Link to comment Share on other sites More sharing options...

0 finbreaker Posted August 23, 2013 Report Share Posted August 23, 2013 Only one of these two solutions actually make sense, though, because a page in a book has two sides, and therefore two page numbers. Quote Link to comment Share on other sites More sharing options...

0 BMAD Posted August 23, 2013 Author Report Share Posted August 23, 2013 unless page 9808 was the last numbered page. But the reason why i prefer the other solution is that the op requested consecutive pages. Quote Link to comment Share on other sites More sharing options...

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## BMAD

From a book, a number of consecutive pages are missing. The sum of the page numbers of these pages is 9808. Which pages are missing?

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