Posted 6 Aug 2013 How can I fabricate (cut,bend,weld) the 1m x 1 m metal sheet into an open top box to hold 75 liters of liquid? 0 Share this post Link to post Share on other sites
0 Posted 7 Aug 2013 1. Cut the sheet into 5 congruent rectangles. 2. Cut&weld each rectangle into a square. 3. Weld 5 squares together into an open top box that can hold (1/5)^(3/2) = 0.0894 m^2 of liquid (more than 89 liters). 0 Share this post Link to post Share on other sites
0 Posted 7 Aug 2013 (edited) 1. Cut the sheet into 5 congruent rectangles. 2. Cut&weld each rectangle into a square. 3. Weld 5 squares together into an open top box that can hold (1/5)^(3/2) = 0.0894 m^2 of liquid (more than 89 liters). That is right! Nice 1 But the maxima solution and the rectangle to square method are under and over design for fabrication. The 9 grids solution is enough for the problem. For the best.. i got the idea from witzars solution.. Edited 7 Aug 2013 by TimeSpaceLightForce 0 Share this post Link to post Share on other sites
0 Posted 7 Aug 2013 (edited) Im trying to edit the weld value of Greek cross solution to 3.788m , this make it cheaper for 9 grids solution to fabricate note: pls hide last figure Edited 7 Aug 2013 by TimeSpaceLightForce 0 Share this post Link to post Share on other sites
0 Posted 7 Aug 2013 Roll sheet into a cylindar that will have the volume of 1 meter times area of opening (Circumference of 1 M) 0 Share this post Link to post Share on other sites
0 Posted 7 Aug 2013 My instincts tell me that half a sphere would give you best results. In this case if you can make half a sphere with area of 1 M^{2} you'd have space for 94 liters. But since you can't make a perfect sphere by cutting and welding, you can try to make it close to a sphere by making a polygon of the highest order as you can, the higher the order the more pieces you'll have to cut and weld 0 Share this post Link to post Share on other sites
0 Posted 9 Aug 2013 Roll sheet into a cylindar that will have the volume of 1 meter times area of opening (Circumference of 1 M) 1)For height=circumference:no base V=h (a) volume h=C=1 height C=piD=1 circumference D=2r=(1/pi) diameter r=1/2/pi radius a=pi(r )^2 circle area V=(1)(pi)(1/2/pi)^2 V= 0.07958 2) For height=diameter :no base a=pi( r)^2 circle area D= 2r=(C/pi) diameter r=C/pi/2 raduis A=1=2rC cylinder area C=1/2/r circumference r=(1/2/r)/pi/2 r=0.28209 V=2r(pi)r^2 volume V=0.14105 good for holding marbles 0 Share this post Link to post Share on other sites
0 Posted 9 Aug 2013 My instincts tell me that half a sphere would give you best results. In this case if you can make half a sphere with area of 1 M^{2} you'd have space for 94 liters. But since you can't make a perfect sphere by cutting and welding, you can try to make it close to a sphere by making a polygon of the highest order as you can, the higher the order the more pieces you'll have to cut and weld 1) volume of sphere=4/3 (Pi) rrr area of sphere=4(pi)rr 1=4(pi)rr r=0.28209 V=0.09403 2) volume of half sphere=2/3 (Pi) rrr area of half sphere=2(pi)rr 1=2(pi)rr r=0.39894 V=0.13298 0 Share this post Link to post Share on other sites
0 Posted 9 Aug 2013 My instincts tell me that half a sphere would give you best results. In this case if you can make half a sphere with area of 1 M^{2} you'd have space for 94 liters. But since you can't make a perfect sphere by cutting and welding, you can try to make it close to a sphere by making a polygon of the highest order as you can, the higher the order the more pieces you'll have to cut and weld1) volume of sphere=4/3 (Pi) rrrarea of sphere=4(pi)rr1=4(pi)rrr=0.28209V=0.094032) volume of half sphere=2/3 (Pi) rrrarea of half sphere=2(pi)rr1=2(pi)rrr=0.39894V=0.13298Yes, the volume is in units of meter^{3}, 1 m^{3} = 1000 liters. 0 Share this post Link to post Share on other sites
Posted
How can I fabricate (cut,bend,weld) the 1m x 1 m metal sheet into an open top box to hold 75 liters of liquid?
Share this post
Link to post
Share on other sites