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I believe if the boy makes a wheel with 7 nodes and a center point, the boy can claim 7 coins and lose three....

unless we claim that after selecting coins the remaining coins either placed by the father or the originals placed by the boy are reexamined for new triangles?/

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I believe if the boy makes a wheel with 7 nodes and a center point, the boy can claim 7 coins and lose three....

unless we claim that after selecting coins the remaining coins either placed by the father or the originals placed by the boy are reexamined for new triangles?/

No, the boy only lose a coin for making 7 and only the boy places all his coins

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Well, if overlapping is not allowed then...

11 is the max

Bingo! Flatlander solution gives 11.

o

o o o o o o

o

But he can do much better.

Remember the centers of identical coins are "above" the table.

So, we're solving for flat triangles formed by coins in 3d space?

Lay 4 coins on the table forming a triangle with the 4th coin in the center. Stack the remaining 4 coins on top of the center coin. If I didn't miss anything then this produces 27 non-overlapping triangles.

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