BMAD Posted April 2, 2013 Report Share Posted April 2, 2013 What would be the remainder of 3^4^5^6^7^... and so on to infinity is when divided by 17? Quote Link to comment Share on other sites More sharing options...
0 dark_magician_92 Posted April 3, 2013 Report Share Posted April 3, 2013 What would be the remainder of 3^4^5^6^7^... and so on to infinity is when divided by 17? Using Euler toitent function and euler theorem -> remainder is 1, as the Dividend is 3^16K (this is obvious) Quote Link to comment Share on other sites More sharing options...
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BMAD
What would be the remainder of 3^4^5^6^7^... and so on to infinity is when
divided by 17?
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