Posted April 2, 2013 What would be the remainder of 3^4^5^6^7^... and so on to infinity is when divided by 17? 0 Share this post Link to post Share on other sites

0 Posted April 3, 2013 What would be the remainder of 3^4^5^6^7^... and so on to infinity is when divided by 17? Using Euler toitent function and euler theorem -> remainder is 1, as the Dividend is 3^16K (this is obvious) 0 Share this post Link to post Share on other sites

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What would be the remainder of 3^4^5^6^7^... and so on to infinity is when

divided by 17?

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