Utkrisht123 Posted March 21, 2013 Report Share Posted March 21, 2013 Look at this pair 42 24 ( digits of 42 are interchanged i.e =24) x 48 x 84 (digits of 48 are interchanged i.e = 84) -------- ---------- 2016 2016 When the digit of multiplicand and multiplier are interchanged then also the result is same. How many such pair can you find? Quote Link to comment Share on other sites More sharing options...
0 TimeSpaceLightForce Posted March 21, 2013 Report Share Posted March 21, 2013 Reveal hidden contents (10a+b) (10c+d) = (10b+a) (10d+c) 63 X 48 = 36 X 84 Quote Link to comment Share on other sites More sharing options...
0 TimeSpaceLightForce Posted March 21, 2013 Report Share Posted March 21, 2013 On 3/21/2013 at 1:27 PM, TimeSpaceLightForce said: Reveal hidden contents (10a+b) (10c+d) = (10b+a) (10d+c) 24 X 63 = 42 X 36 Quote Link to comment Share on other sites More sharing options...
0 dark_magician_92 Posted March 21, 2013 Report Share Posted March 21, 2013 On 3/21/2013 at 10:40 AM, Utkrisht123 said: Look at this pair 42 24 ( digits of 42 are interchanged i.e =24) x 48 x 84 (digits of 48 are interchanged i.e = 84) -------- ---------- 2016 2016 When the digit of multiplicand and multiplier are interchanged then also the result is same. How many such pair can you find? If you are asking for 2 digit numbers, then Reveal hidden contents lets say the numbers are AB and CD, then this property is true if A*C=B*D. eg. 14*82, 24*63 and so on.... Quote Link to comment Share on other sites More sharing options...
0 Debasis Posted March 21, 2013 Report Share Posted March 21, 2013 Reveal hidden contents let the two numbers be=10a+b and 10x+y so acc. to given condition , (10a+b)* (10x+y)=(10b+a)*(10y+x) solving we get ax=by in such cases ....so there can be infinetely many possible combinations in which AB*XY=BA*YX the only req. is A*X=B*Y.. Quote Link to comment Share on other sites More sharing options...
0 TimeSpaceLightForce Posted March 21, 2013 Report Share Posted March 21, 2013 (edited) Reveal hidden contents ( 10Na+a )(10b+Nb)=(10a+Na)(10Nb+b) N(2,3,4) 12: 42 84 63 6 pairs 13: 62 93 3 pairs 14: 28 1 pair Edited March 21, 2013 by TimeSpaceLightForce Quote Link to comment Share on other sites More sharing options...
0 nakulendu Posted March 22, 2013 Report Share Posted March 22, 2013 Reveal hidden contents 10 pairs in all. 6 of the pairs are truly 2 digit number pairs: 1. (12, 42 ) (21, 24) 2. (13, 62 ) (31, 26) 3. (14, 82 ) (41, 28) 4. (23, 64) (32, 46) 5. (24, 84) (42, 48) ... already listed 6. (34, 86) (43, 68) 4 additional the pairs can be had where there is a 1 digit number in each pair e.g. you take 1 as 01 and the reversing digits you get 10 ). These are a. (1, 20) (10, 2) b. (2,40) (20,4) c. (3,60) (30,6) d. (4,80) (40,8) I guess this is it. Didn't get into 3 digit numbers because rules of switching digits as shown in example gets cloudy Quote Link to comment Share on other sites More sharing options...
0 nakulendu Posted March 22, 2013 Report Share Posted March 22, 2013 On 3/22/2013 at 6:08 AM, nakulendu said: Reveal hidden contents 10 pairs in all. 6 of the pairs are truly 2 digit number pairs: 1. (12, 42 ) (21, 24) 2. (13, 62 ) (31, 26) 3. (14, 82 ) (41, 28) 4. (23, 64) (32, 46) 5. (24, 84) (42, 48) ... already listed 6. (34, 86) (43, 68) 4 additional the pairs can be had where there is a 1 digit number in each pair e.g. you take 1 as 01 and the reversing digits you get 10 ). These are a. (1, 20) (10, 2) b. (2,40) (20,4) c. (3,60) (30,6) d. (4,80) (40,8) I guess this is it. Didn't get into 3 digit numbers because rules of switching digits as shown in example gets cloudy Reveal hidden contents pure 2 digit pairs - 12 and tohose which have a 1 digit number as well as above - 4 Quote Link to comment Share on other sites More sharing options...
Question
Utkrisht123
Look at this pair
42 24 ( digits of 42 are interchanged i.e =24)
x 48 x 84 (digits of 48 are interchanged i.e = 84)
-------- ----------
2016 2016
When the digit of multiplicand and multiplier are interchanged then also the result is same.
How many such pair can you find?
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